Let its dimensions be a, b and c:-
Surface area of the cuboid: 2*(a*b)+2*(b*c)+2*(a*c) in square units
First you need to know the size
the total surface area of a cuboid is : 2(lw+wh+hl) where l is length, w is width, and h is height.
The answer should be: (2*a*b)+(2*b*c)+(2*c*a)
the formula for the volume of a cuboid is length x breadth x height
For a cuboid (a 3D rectangle) of width W, height H and depth D, the surface area is: (WH + WD + HD) x 2.
derivation of surface area of cuboid
Volume = Height × Width × Depth Surface area=2(lw+wh+hl)
The surface area of a box, which is a cuboid, depends on its length, width and height. A cube is a special type of cuboid in which the length , width and height are all the same.
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
Lateral surface area of a cuboid = 2 (Length + Breadth) × Height Lateral surface area of a cube = 4 × Side2
A cuboid is a 3 dimensional object and 3 measures are required for the total surface area of a cuboid.
Add all the area of six faces of the box in gerneral the surface area of a cube shape box is 6a2 and of cuboid is 2(lb x bh x hl)
Volume of a cuboid = cross-section area times its length
yes
Make it infinitesimally small.
First you need to know the size
2(l*w)+2(l*h)+2(w*h) * * * * * That is only true for a cuboid. Other bodies also have surface areas and there are lots of formulae dealing with them.