N squared would be used to find the square root of a number or numbers. In order to find the number of three digit numbers such that the sum of the square results of any two digits are equal to the third digit the use of the formula (HOE)squared=Hsquared*10000+2HE*100+Esquared is needed.
x64 is not a perfect square any number if it is a 3-digit perfect square and ending with 4 it can be 144,324 ,484 and 784 because the number is ending with 4 but the tens digit is not matching to any of the option so it is not a perfect square
Same as you would square any other number - multiply it by itself.
The smallest 5 digit number is 10000 = 1002 The largest 5 digit number is 99999 and 3162 < 99999 < 3172 So, take any number between 100 and 316 (both inclusive) and square it to get a 5-digit perfect square.
This is not true. Think about any 4 digit multiplied by 1. This remains a 4 digit. In the case of any 4 digit under 5000, multiplied by two would also be a 4 digit number
N squared would be used to find the square root of a number or numbers. In order to find the number of three digit numbers such that the sum of the square results of any two digits are equal to the third digit the use of the formula (HOE)squared=Hsquared*10000+2HE*100+Esquared is needed.
x64 is not a perfect square any number if it is a 3-digit perfect square and ending with 4 it can be 144,324 ,484 and 784 because the number is ending with 4 but the tens digit is not matching to any of the option so it is not a perfect square
Same as you would square any other number - multiply it by itself.
The smallest 5 digit number is 10000 = 1002 The largest 5 digit number is 99999 and 3162 < 99999 < 3172 So, take any number between 100 and 316 (both inclusive) and square it to get a 5-digit perfect square.
There is no three digit prime number whose square root is a prime number. Prime numbers have no factors other than 1 and themselves. Any number having a prime number as a square root is a composite number.
The answer is vague but correct . Take any prime number and any other number whose combined digit length is 401 and their product will generate a 400 or a 401 digit number.
Multiply it by itself.
Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.
no
Well, honey, let me break it down for you. When you multiply a 4-digit number (ranging from 1000 to 9999) by a 1-digit number (ranging from 0 to 9), the result can be a 3-digit number (ranging from 0 to 8991). So no, the product of a 4-digit number and a 1-digit number is not always a 5-digit number. Math doesn't discriminate, darling.
This is not true. Think about any 4 digit multiplied by 1. This remains a 4 digit. In the case of any 4 digit under 5000, multiplied by two would also be a 4 digit number
To be conclusively positive, it works the same for any size number, you have to try to divide it by every number up through its square root.