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Where is center of mass of a sphere?
The center of mass of a sphere is its geometric center.
What is the mass of a sphere of radius 4cm?
To find the mass of a sphere, you need to know its density in addition to its volume. The volume ( V ) of a sphere can be calculated using the formula ( V = \frac{4}{3} \pi r^3 ). For a sphere with a radius of 4 cm, the volume would be approximately 268.08 cm³. If you provide the density of the material the sphere is made of, the mass can be calculated using the formula ( \text{mass} = \text{density} \times \text{volume} ).
How do you find the density of a sphere given its mass and radius?
Density = mass/ volume volume= 4/3(pie)(r^3) ***r= radius in meters** so find volume then divide mass by volume and there you go.
How do you derive the moment of inertia of solid sphere?
mass moment of inertia for a solid sphere: I = (2 /5) * mass * radius2 (mass in kg, radius in metres)
How do you find the mass of a sphere with a radius of 4.7 mm and a length of 3.9mm?
First and foremost, you must know the density. Mass is the product of volumeand density (m=vd). Also, a sphere is specified by its radius alone. The "length"of a sphere should represent nothing more than its diameter, which is twice itsradius.==============================Answer #2:First of all, that's no sphere, since spheres don't have 'length'.Next . . . As written, the question has no answer, simply because the mass ofa sphere doesn't depend on its size. A hundred spheres can easily all have thesame size but a hundred different masses.
What is the formula for a sphere mass?
how do you find the mass of a sphere Volume x density => 4/3(pi)(r)3 x density
How do you find mass of a sphere when only radius is given?
Volume of a sphere = 4/3*pi*radius3 Surface area of a sphere = 4*pi*radius2
Where is center of mass of a sphere?
The center of mass of a sphere is its geometric center.
How do you find density of a sphere?
you have to divide the mass by the volume then measure the ends then you found your answer
The sphere is made of aluminum and its mass is 26 kg. 1) What is the radius of the sphere?
To find the radius of the aluminum sphere, you need to know its density. Without density information, it's not possible to calculate the radius just from the mass given.
What is the formula for the mass of a sphere?
The mass of a sphere is 4/3*pi*r3*d where r is the radius of the sphere and d is the density of the material of the sphere.
How do you find the volume of a sphere giving the mass and density?
Volume of anything = (its mass) divided by (its density) regardless of what shape it happens to be.
How do you find the mass density of a sphere who's mass is 5000 grams?
Density is the mass per unit volume. e.g. kg/m3. But you've only given one of the quantities needed - we still need the volume of the sphere.
A solid aluminum sphere has a mass of 88g Use the density of aluminum to find radius of sphere?
Density = mass / volume. You have the density of aluminum and the mass of the aluminum sphere. The volume of a sphere is 4/3*Pi*r^3. Therefore volume = 4/3*Pi*r^3 = mass / density. Solve for r, which is the radius of the sphere.
Density of a sphere?
you need the mass and radius of the sphere- density = mass divided by volume, so mass/volume. the volume of a sphere is 4 divided by 3 multiplied by pi multiplied by the radius squared. 4/3(π)(r^2).
What is the mass of a sphere of radius 4cm?
To find the mass of a sphere, you need to know its density in addition to its volume. The volume ( V ) of a sphere can be calculated using the formula ( V = \frac{4}{3} \pi r^3 ). For a sphere with a radius of 4 cm, the volume would be approximately 268.08 cm³. If you provide the density of the material the sphere is made of, the mass can be calculated using the formula ( \text{mass} = \text{density} \times \text{volume} ).
If the mass of a sphere is 75 grams what is the volume?
To find the volume of the sphere, you need to know the density of the material the sphere is made of. With just the mass provided (75 grams), you cannot calculate the volume without this additional information.
