Volume of a sphere = 4/3*pi*radius3
Surface area of a sphere = 4*pi*radius2
Provided they are the same thickness, the larger sphere will have a radius of 10.165cm
Its diameter is 2R, whatever the mass.
I believe it is I = mk^2 where k is radius of gyration and m is mass.
Density = Mass/Volume so Volume = Mass/Density. Therefore the Volume can be calculated. Volume = Area [of cross section] * Width So Width = Volume/Area.
Basically radius of gyration of a substance is defined as that distance from the axis of rotation from which if equivalent mass that of the substance is kept will have exactly the same moment of inertia about that axis of the substance.
Density = mass/ volume volume= 4/3(pie)(r^3) ***r= radius in meters** so find volume then divide mass by volume and there you go.
Not sure how a radio can help. If you are given the radius (including units) of a sphere, the volume is 4/3*pi*r3 cubic units. Then mass = density*volume, in the appropriate units.
The mass of a sphere is 4/3*pi*r3*d where r is the radius of the sphere and d is the density of the material of the sphere.
you need the mass and radius of the sphere- density = mass divided by volume, so mass/volume. the volume of a sphere is 4 divided by 3 multiplied by pi multiplied by the radius squared. 4/3(π)(r^2).
mass moment of inertia for a solid sphere: I = (2 /5) * mass * radius2 (mass in kg, radius in metres)
Vol(3)/Vol(2.5) = 33/2.53 = 1.23 So Mass(3) = 1.23*Mass(2.5) = 1.23*500 = 864 grams
Provided they are the same thickness, the larger sphere will have a radius of 10.165cm
Mass is conserved which means that a body will have the same mass wherever it goes. But at the centre of a masive sphere the body has no gravity acting on it so its weight is zero. At an intermediated radius the force on it is obviously less than at the surface, and Isac Newton proved that a body at a given distance inside a sphere feels a gravitational force from a sub-sphere of radius equal the distance of the body from the centre. In other words the body feels no gravity from the shell outside its own radius.
You need to know if the sphere is solid or hollow. You also need the "density" in terms of pounds weight per unit volume. Then Volume = Mass/Density And Radius = cuberoot[3*Vol/(4*pi)]
Density = mass / volume. You have the density of aluminum and the mass of the aluminum sphere. The volume of a sphere is 4/3*Pi*r^3. Therefore volume = 4/3*Pi*r^3 = mass / density. Solve for r, which is the radius of the sphere.
Density is the mass per unit volume. e.g. kg/m3. But you've only given one of the quantities needed - we still need the volume of the sphere.
The Schwarzschild radius is a concept related to black holes. Given a body it is the radius such that, if all the mass of the body were squeezed (uniformly) within that sphere, then the escape velocity at the surface of the velocity would be equal to the speed of light.