If the sequence is taken to start 1,1,2,... then the 100th term is 354,224,848,179,261,915,075 And you've got to hope I have typed that in correctly!
The 100th pentagonal number is 14950.
you replace the "n" with ahundred e.g... if it's 2n+1, you will go 2x100+ 1 which is 201
"The recursive form is very useful when there aren't too many terms in the sequence. For instance, it would be fairly easy to find the 5th term of a sequence recursively, but the closed form might be better for the 100th term. On the other hand, finding the closed form can be very difficult, depending on the sequence. With computers or graphing calculators, the 100th term can be found quickly recursively."
The nth triangulat number is n*(n+1)/2 The 100th is 100*101/2 = 5050
It is 354,224,848,179,261,915,075.
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
If the sequence is taken to start 1,1,2,... then the 100th term is 354,224,848,179,261,915,075 And you've got to hope I have typed that in correctly!
ive been told u hve 2 times sumfin bii sumfin
The 100th Fibonacci number is 354,224,848,179,261,915,075.
The 100th pentagonal number is 14950.
you replace the "n" with ahundred e.g... if it's 2n+1, you will go 2x100+ 1 which is 201
The 100th prime number is 541.
"The recursive form is very useful when there aren't too many terms in the sequence. For instance, it would be fairly easy to find the 5th term of a sequence recursively, but the closed form might be better for the 100th term. On the other hand, finding the closed form can be very difficult, depending on the sequence. With computers or graphing calculators, the 100th term can be found quickly recursively."
The nth triangulat number is n*(n+1)/2 The 100th is 100*101/2 = 5050
If you mean: 34 39 24 ... then the nth term is 39-5n and so the 100th term = -461
596