Find the formula of it.
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence is decreasing by 6 each time. Therefore, the nth term can be represented by the formula: 18 - 6(n-1), where n is the position of the term in the sequence.
6n-5 is the nth term of this sequence
The nth term is (36 - 4n)
If you mean: 34 39 24 ... then the nth term is 39-5n and so the 100th term = -461
you replace the "n" with ahundred e.g... if it's 2n+1, you will go 2x100+ 1 which is 201
Find the formula of it.
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.
i dont get it
If the sequence is non-linear, you need to establish how it is defined.
123456789 * * * * * The nth term is 3n
The nth term is Un = a + (n-1)*d where a = U1 is the first term, and d is the common difference.
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence is decreasing by 6 each time. Therefore, the nth term can be represented by the formula: 18 - 6(n-1), where n is the position of the term in the sequence.
6n-5 is the nth term of this sequence
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4