You didn't specify the equation. A minimum or maximum value of a function is often found by calculating the derivative of a function, writing an equation for derivative equal to zero, and then analyzing points where the derivative either doesn't exist, or is equal to zero. You'll find find information about this in introductory calculus books.
I would be happy to help you find the value of y, but I need to see the equation you're referring to. Please provide the equation so I can assist you further!
-- In the equation of the graph, set x=0. -- Solve the equation for 'y'. -- The value you get for 'y' when x=0 is the y-intercept.
To find the y-intercept of a line, set the x-coordinate to zero in the line's equation. For example, if the equation is in the form (y = mx + b), the y-intercept is simply the value of (b). If the equation is in standard form, (Ax + By = C), rearrange it to solve for (y) when (x = 0). The resulting value of (y) at that point is the y-intercept.
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The value if Y in 16y times 164 would be 10. This is a math problem.
You solve an equation containing y.
I would be happy to help you find the value of y, but I need to see the equation you're referring to. Please provide the equation so I can assist you further!
-- In the equation of the graph, set x=0. -- Solve the equation for 'y'. -- The value you get for 'y' when x=0 is the y-intercept.
To find the y-intercept of a line, set the x-coordinate to zero in the line's equation. For example, if the equation is in the form (y = mx + b), the y-intercept is simply the value of (b). If the equation is in standard form, (Ax + By = C), rearrange it to solve for (y) when (x = 0). The resulting value of (y) at that point is the y-intercept.
The y-intercept is the value of a function f when x is equal to zero. So, substitute 0 for x into the equation and find the value of y.
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Find the value of y in this equation: 16y = 164.Answer: 10 1/4
The value if Y in 16y times 164 would be 10. This is a math problem.
plug in a 0 for the "x" value of the equation, and solve it :D
2x+5 = 62 and 3x-y = 23.3 x = 28.5 and y = 62.2 Solve the first equation and then substitute the value of x into the second equation to find the value of y.
Find (or calculate) the equation of the line. Select any value of x. Calculate the corresponding value for y using the equation. Then (x, y) is a point on the same line.
To find the value of ( y ) in the equation ( y = 3x - 1 ) when ( x = -3 ), substitute (-3) for ( x ): [ y = 3(-3) - 1 = -9 - 1 = -10 ] Thus, when ( x = -3 ), ( y ) is (-10).