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To find the angle represented by (3x), first, you need to know the value of (x). If you have an equation or context where (x) is defined, substitute that value into (3x). For example, if (x = 20^\circ), then (3x = 3 \times 20^\circ = 60^\circ). If additional information is provided (like the sum of angles in a polygon), you can use that to solve for (x) first.
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HELP PLEAS Quadrilateral rstu is a rectangle if the measure of angle RSU equals7x - 10 and the measure of angle UST equals 3x plus 15 find x?
A picture would help. If I've reconstructed it correctly, it appears that RSU is a 90 degree angle and UST is a 45. That means that 1/2(7x - 10) = 3x + 15 x = 40
Two angles are supplementaryOne angle is 60 degrees more thatn twice the other Find the angles?
Supplementary angles, when added together, equal 180 degrees. If we let the smaller angle equal X we know that X + (2X + 60) = 180 3X+60=180 3X=120 X=40 The small angle is 40 degrees. The larger angle is 2(40)+60=140 degrees.
The second angle of a triangle is four times as large as the first The third angle is 10 degrees more than three times the first angle Find the measure of the first angle?
Let x equal the first angle.let 4x= the second anglelet 3x+10x+4x+3x+10=180 The sum of the interior angle measures of a triangle is 180 degrees.8x+10=180 combine like terms8x=170 addition(subtraction) property of equalityx=21.25 degrees
If angle a and B are supplementary angles and angle a is two times as large as angle B find the measures of angle and angle B?
If angles A and B are supplementary, their measures add up to 180 degrees. Let angle B be ( x ). Then angle A, being twice as large, is ( 2x ). Setting up the equation, we have ( x + 2x = 180 ), which simplifies to ( 3x = 180 ). Solving for ( x ), we find ( x = 60 ) degrees for angle B, and angle A measures ( 120 ) degrees. Thus, angle A is 120 degrees and angle B is 60 degrees.
When two angles are added together the answer is 93. one angle is double the other. what is the size of the larger angle?
Let the larger angle be 2x and the smaller angle be x: 2x+x = 93 3x = 93 Divide both sides by 3 to find the value of x: x = 31 Therefore the larger angle is 62 degrees.
If the measure of an angle is three times the measure of its supplement then find the measure of the angle?
x is the angle you're looking for and 3x is the angle that when added to x must total 180 degrees. Therefore the angle is 45degrees (x + 3x = 180)
Angle abc is congruent to angle def Angle A is 22 degrees Angle D is 5y-3 degrees Find x y Given are the hypotenuse of 9 and 3x?
Angle_abc_is_congruent_to_angle_def_Angle_A_is_22_degrees_Angle_D_is_5y-3_degrees_Find_x_y_Given_are_the_hypotenuse_of_9_and_3x
If measure angle 3 equals x2 plus 4x what is the possible measure of angle 3?
If measure angle 3 = x2 + 4x and measure angle 5 = 3x + 72, find the possible measures of angle 3 and angle 5
In a triangle the measure of the middle angle is triple the measure of the smallest angle and the measure of the largest angle is 55 degrees greater then the measure of the smalest angle Find measures?
x + (3x) + (x + 55) = 1805x + 55 = 1805x = 125x = 25 . . . 3x = 75 . . . x+55 = 80Check . . . 25 + 75 + 80 = 180 yay!
The measure of the supplement of an angle is 60 less than three times the measure of the complement of the angle Find the measure of the angle?
<p><p> 180-x=3(90-x)-60 180-x=270-3x-60 3x-x=270-180-60 2x=30 x=15
What is the sum of the measures of two complementary angles is 90 If one angle measure is 24 more than twice the measure of the other find the smaller angle?
Angle A = X degrees Angle B = 2X + 24 A+B = 3X + 24 But A+B = 90, so 90 = 3x + 24 90 - 24 = 3x 66 = 3x 22 = x So, Angle A = 22º and Angle B = 22+22+24 = 68º Here's how to get that answer: if 2 angles equal 90 degrees, and one angle is 24 more than twice the measure of the other angle, set up an equation with a variable. Say x is the variable. One angle is 2x+24 because it's twice what x is plus 24. The other angle is x. 2x+24+x+90 Now solve. Combine the x's to make the equation 3x+24=90. Now subtract 24 from 90 to get 66. 3x=66 Now divide 66 by 3. x=22. We now have to find the measures of both angles. 2x=44, and 44+24=68 the smaller angle is 22 degrees and the bigger angle is 68 degrees. We know this is right because 22+68=90.
HELP PLEAS Quadrilateral rstu is a rectangle if the measure of angle RSU equals7x - 10 and the measure of angle UST equals 3x plus 15 find x?
A picture would help. If I've reconstructed it correctly, it appears that RSU is a 90 degree angle and UST is a 45. That means that 1/2(7x - 10) = 3x + 15 x = 40
If two angles are supplementary and one angle is twice as large and the other find the number of degrees in the measure of the smaller angle?
A+b=180 x+2x=180 3x=180 x=60
Two angles are supplementaryOne angle is 60 degrees more thatn twice the other Find the angles?
Supplementary angles, when added together, equal 180 degrees. If we let the smaller angle equal X we know that X + (2X + 60) = 180 3X+60=180 3X=120 X=40 The small angle is 40 degrees. The larger angle is 2(40)+60=140 degrees.
A base angle of an isosceles triangle is 9 degrees more than the vertex angle Find the vertex angle?
let the vertex angle be x degrees, then the base angle is x + 9 degrees. Since in a triangle the sum of the angle is 180 degrees, and the base angles in an isosceles triangle are congruent, we have: x + 2(x + 9) = 180 x + 2x + 18 = 180 3x + 18 = 180 subtract 18 to both sides 3x = 162 divide by 3 to both sides x = 54 Thus the vertex angle is 54 degrees.
The second angle of a triangle is four times as large as the first The third angle is 10 degrees more than three times the first angle Find the measure of the first angle?
Let x equal the first angle.let 4x= the second anglelet 3x+10x+4x+3x+10=180 The sum of the interior angle measures of a triangle is 180 degrees.8x+10=180 combine like terms8x=170 addition(subtraction) property of equalityx=21.25 degrees
If angle a and B are supplementary angles and angle a is two times as large as angle B find the measures of angle and angle B?
If angles A and B are supplementary, their measures add up to 180 degrees. Let angle B be ( x ). Then angle A, being twice as large, is ( 2x ). Setting up the equation, we have ( x + 2x = 180 ), which simplifies to ( 3x = 180 ). Solving for ( x ), we find ( x = 60 ) degrees for angle B, and angle A measures ( 120 ) degrees. Thus, angle A is 120 degrees and angle B is 60 degrees.
