A picture would help. If I've reconstructed it correctly, it appears that RSU is a 90 degree angle and UST is a 45. That means that 1/2(7x - 10) = 3x + 15 x = 40
Supplementary angles, when added together, equal 180 degrees. If we let the smaller angle equal X we know that X + (2X + 60) = 180 3X+60=180 3X=120 X=40 The small angle is 40 degrees. The larger angle is 2(40)+60=140 degrees.
Let x equal the first angle.let 4x= the second anglelet 3x+10x+4x+3x+10=180 The sum of the interior angle measures of a triangle is 180 degrees.8x+10=180 combine like terms8x=170 addition(subtraction) property of equalityx=21.25 degrees
Let the larger angle be 2x and the smaller angle be x: 2x+x = 93 3x = 93 Divide both sides by 3 to find the value of x: x = 31 Therefore the larger angle is 62 degrees.
to find sin 35 here we take the angle = x=15 then 3x=45 , 4x=60 then 4x-3x=60-45 then by putting sin on rhs we will get cos 35 and sin 35 hope it helped you
x is the angle you're looking for and 3x is the angle that when added to x must total 180 degrees. Therefore the angle is 45degrees (x + 3x = 180)
Angle_abc_is_congruent_to_angle_def_Angle_A_is_22_degrees_Angle_D_is_5y-3_degrees_Find_x_y_Given_are_the_hypotenuse_of_9_and_3x
If measure angle 3 = x2 + 4x and measure angle 5 = 3x + 72, find the possible measures of angle 3 and angle 5
x + (3x) + (x + 55) = 1805x + 55 = 1805x = 125x = 25 . . . 3x = 75 . . . x+55 = 80Check . . . 25 + 75 + 80 = 180 yay!
<p><p> 180-x=3(90-x)-60 180-x=270-3x-60 3x-x=270-180-60 2x=30 x=15
Angle A = X degrees Angle B = 2X + 24 A+B = 3X + 24 But A+B = 90, so 90 = 3x + 24 90 - 24 = 3x 66 = 3x 22 = x So, Angle A = 22º and Angle B = 22+22+24 = 68º Here's how to get that answer: if 2 angles equal 90 degrees, and one angle is 24 more than twice the measure of the other angle, set up an equation with a variable. Say x is the variable. One angle is 2x+24 because it's twice what x is plus 24. The other angle is x. 2x+24+x+90 Now solve. Combine the x's to make the equation 3x+24=90. Now subtract 24 from 90 to get 66. 3x=66 Now divide 66 by 3. x=22. We now have to find the measures of both angles. 2x=44, and 44+24=68 the smaller angle is 22 degrees and the bigger angle is 68 degrees. We know this is right because 22+68=90.
A picture would help. If I've reconstructed it correctly, it appears that RSU is a 90 degree angle and UST is a 45. That means that 1/2(7x - 10) = 3x + 15 x = 40
A+b=180 x+2x=180 3x=180 x=60
Supplementary angles, when added together, equal 180 degrees. If we let the smaller angle equal X we know that X + (2X + 60) = 180 3X+60=180 3X=120 X=40 The small angle is 40 degrees. The larger angle is 2(40)+60=140 degrees.
let the vertex angle be x degrees, then the base angle is x + 9 degrees. Since in a triangle the sum of the angle is 180 degrees, and the base angles in an isosceles triangle are congruent, we have: x + 2(x + 9) = 180 x + 2x + 18 = 180 3x + 18 = 180 subtract 18 to both sides 3x = 162 divide by 3 to both sides x = 54 Thus the vertex angle is 54 degrees.
Let x equal the first angle.let 4x= the second anglelet 3x+10x+4x+3x+10=180 The sum of the interior angle measures of a triangle is 180 degrees.8x+10=180 combine like terms8x=170 addition(subtraction) property of equalityx=21.25 degrees
Let the larger angle be 2x and the smaller angle be x: 2x+x = 93 3x = 93 Divide both sides by 3 to find the value of x: x = 31 Therefore the larger angle is 62 degrees.