60 x 7 = 420
3 x 7 = 21
420 + 21 + 441
63 x 7 = 441
numbers are multiplied to find products
To find the partial products of 15 multiplied by 32, we can break it down using the distributive property. We can express 15 as (10 + 5) and 32 as (30 + 2). The partial products are calculated as follows: 10 x 30 = 300 10 x 2 = 20 5 x 30 = 150 5 x 2 = 10 Adding these together (300 + 20 + 150 + 10) gives a total of 480.
To find the partial products of 28 and 43, you can break down the multiplication into simpler parts. First, multiply 28 by 3 (the tens place of 43), which gives you 84 (28 × 3). Then, multiply 28 by 40 (the tens place of 43 multiplied by 10), resulting in 1120 (28 × 40). The partial products are 84 and 1120.
To find the answer using partial products, you break down each number into its place values. For example, if you are multiplying 23 by 45, you can separate 23 into 20 and 3, and 45 into 40 and 5. Then, multiply each pair of place values: 20 × 40, 20 × 5, 3 × 40, and 3 × 5. Finally, add all the partial products together to get the final answer.
To find 67 times 83 using partial products, you can break down the numbers into simpler components. For example, you can express 67 as 60 + 7 and 83 as 80 + 3. Then, you can calculate the partial products: 60 × 80, 60 × 3, 7 × 80, and 7 × 3, and finally sum those products to get the final result.
numbers are multiplied to find products
how to find the partial products of a number
To find the partial products of 15 multiplied by 32, we can break it down using the distributive property. We can express 15 as (10 + 5) and 32 as (30 + 2). The partial products are calculated as follows: 10 x 30 = 300 10 x 2 = 20 5 x 30 = 150 5 x 2 = 10 Adding these together (300 + 20 + 150 + 10) gives a total of 480.
To find the partial products of 28 and 43, you can break down the multiplication into simpler parts. First, multiply 28 by 3 (the tens place of 43), which gives you 84 (28 × 3). Then, multiply 28 by 40 (the tens place of 43 multiplied by 10), resulting in 1120 (28 × 40). The partial products are 84 and 1120.
To find the answer using partial products, you break down each number into its place values. For example, if you are multiplying 23 by 45, you can separate 23 into 20 and 3, and 45 into 40 and 5. Then, multiply each pair of place values: 20 × 40, 20 × 5, 3 × 40, and 3 × 5. Finally, add all the partial products together to get the final answer.
511 and 2100
To find 67 times 83 using partial products, you can break down the numbers into simpler components. For example, you can express 67 as 60 + 7 and 83 as 80 + 3. Then, you can calculate the partial products: 60 × 80, 60 × 3, 7 × 80, and 7 × 3, and finally sum those products to get the final result.
It is easier to multiply
To find the partial products for 128 x 43, we can break down the multiplication using the distributive property. We can express 43 as 40 + 3. Therefore, the partial products are calculated as follows: 128 x 40 = 5120 and 128 x 3 = 384. Adding these together gives the total: 5120 + 384 = 5504.
To find the partial pressure at equilibrium in a chemical reaction, you can use the equilibrium constant expression and the initial concentrations of the reactants and products. Calculate the equilibrium concentrations of each species using the stoichiometry of the reaction and then use these concentrations to determine the partial pressures.
The answer is to smell my penis
16 and 240