Q: How do you find the area of a segment determined by a major arc?

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if it is the radius you can find area or circumference

The formula to find the area of the segment is given below. It can also be found by calculating the area of the whole pie-shaped sector and subtracting the area of the isosceles triangle △ACB.Formula for the area of a segment of a circle where:C is the central angle in DEGREES R is the radius of the circle of which the segment is a part.π is Pi, approximately 3.142sin is the trigonometry Sine function.

Make the segment into a square, find the area of the square, then find the square root of the area because the square root is equal to the side length

fulse

I think that you draw a square from that line, and find the area of that square.

Related questions

if it is the radius you can find area or circumference

The formula to find the area of the segment is given below. It can also be found by calculating the area of the whole pie-shaped sector and subtracting the area of the isosceles triangle △ACB.Formula for the area of a segment of a circle where:C is the central angle in DEGREES R is the radius of the circle of which the segment is a part.π is Pi, approximately 3.142sin is the trigonometry Sine function.

In order to find the area of a sector of a circle you can use the formula below: pi*r^2 * # of degrees/ 360

Make the segment into a square, find the area of the square, then find the square root of the area because the square root is equal to the side length

fulse

The solution depends on the information supplied. Basically, you find the area of the sector containing the segment and then deduct the area of the triangle formed by the chord and the two radii enclosing the sector. If you are given the radius(r) of the circle and the height(h) then construct a radius that is perpendicular to and bisects the chord. This will create two congruent triangles which together form the main triangle. Using Pythagoras enables the half-chord length to be calculated as the hypotenuse is r and the height (also the length of the third side) is r-h. With this information the full chord length can be established and thus the area of the main triangle. Using sine or cosine methods enables the sector angle at the centre to be calculated and thus the sector area. Simple subtraction produces the area of the segment. If you are given the radius and the chord(c) length then the construction referred to above enables the height of the main triangle to be calculated and a similar process will generate the area of that triangle and the sector area. This, in turn, will enable the segment area to be determined.

There must be an equilateral triangle within the sector of the circle and so:- Area of sector: 60/360*pi*12*12 = 75.39822369 Area of triangle: 0.5*12*12*sin(60 degrees) = 62.35382907 Area of segment: 75.39822369-62.35382907 = 13.04439462 or about 13 square units

SeGmEnT Pd

I think that you draw a square from that line, and find the area of that square.

It could be that there is no major supplier or that they are not very popular in that particualr area. Try looking in major supermarkets or online if you really want to find them.

Area of sector/Area of circle = Angle of sector/360o Area of sector = (Area of circle*Angle of sector)/360o

If the area of a circle is known, the radius can be determined using the area formula: A =Ï€ r2, (r = radius, Ï€ = to 3.14)A/Ï€ = r2,âˆš(A/Ï€) [divide the Area by Ï€, then find the square root of the result ] = r,Then, find the diameter (twice the radius): d = 2r.