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There must be an equilateral triangle within the sector of the circle and so:-

Area of sector: 60/360*pi*12*12 = 75.39822369

Area of triangle: 0.5*12*12*sin(60 degrees) = 62.35382907

Area of segment: 75.39822369-62.35382907 = 13.04439462 or about 13 square units

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Q: How do you find the area of a segment of a circle if the radius of the circle and the chord of the segment each have length 12?
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