Area of a semicircle = (pi*radius^2)/2
Find the area of the whole circle and divide by two. Area of semicircle = 0.5*pi*r2, where pi = 3.14159 and r is the radius
The circumference of a circle is 2{pi}r. So, for a semicircle it is half this, that is {pi}r. The perimeter of the semicircle is the round bit ({pi}r) plus a diameter of the circle (2r) perimeter = {pi}4 + 2 x 4 ~= 20.6 in Area of a circle is {pi}r2, so for a semicircle it is half this. area ={pi}42 / 2 ~= 25.1 in2.
Area in square inches = (pi*radius^2)/2
The area is 0.5*pi*r2 where r is the radius. The angle is totally irrelevant since it will always by 180 degrees for a semicircle!
Pi*radius squared is how to find the area of a semicircle
Area of a semicircle = (pi*radius^2)/2
Find the area of the whole circle and divide by two. Area of semicircle = 0.5*pi*r2, where pi = 3.14159 and r is the radius
The area of a semicircle is half of the area of a circle. The area of a circle is pi x radius x radius. So the area of a semicircle is 1/2 x pi x radius x radius or (pi x radius x radius) / 2.
It is 27.49 units.
An area of a circle is pi*r2 - so an area of a semicircle is 0.5*pi*r2: 0.5*3.14*42 = 25.13 square meters
Diameter of semicircle = 1 Area of semicircle = Pi/8 Area of triangle = 0.25 Area outside triangle = (Pi/8) - 0.25 = 0.1427 (rounded to 4th decimal).
The circumference of a circle is 2{pi}r. So, for a semicircle it is half this, that is {pi}r. The perimeter of the semicircle is the round bit ({pi}r) plus a diameter of the circle (2r) perimeter = {pi}4 + 2 x 4 ~= 20.6 in Area of a circle is {pi}r2, so for a semicircle it is half this. area ={pi}42 / 2 ~= 25.1 in2.
Area in square inches = (pi*radius^2)/2
The circumference of a semicircle is pi times the radius plus the diameter.
That would depend on the radius which has not been given but the area of the semi circle will be (pi*radius squared)/2
The equation for area of a circle is A=pi x R x R. A semicircle is half a circle, so we calculate the area of a circle and divide by 2. The area of the circle would be approximately 1384.74. Thus the area of the semicircle would be 692.37.