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It is obvious from the coordinates that, if A = (-1, -1), B = (3, -1) and C = (-1, 2) thenAB is horizontal and of length 4

AC is vertical and of length 3

So ABC is right angled with legs of length 3 and 4 and so with an area of 6 square units.

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Q: How do you find the area of a triangle (-1-1) (3-1) (-12)?
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