A triangle with side a: 7, side b: 12, and side c: 11 units has an area of 37.95 square units.
Given this area, the sides measure 52.92734 cm
The two equal sides each measure 8 inches
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
The area is 1.2 (1.16463) m2
It is not possible to answer the question with only the lengths of two sides of a triangle.
The area of triangle is : 340.0
The area of triangle is : 340.0
It depends on what you wish to measure: the lengths of sides, the angles, the area, the perimeter.
Yes. The two equal sides would measure 3.
Area of a triangle is 1/2*Base*Height. I believe you can take it from here.
Given this area, the sides measure 52.92734 cm
A square metre is a measure of area and you would not normally measure a square metre. You would measure the linear dimensions of the shape and calculate the area.One reason that you would not measure a square metre is that it can come in all shapes:a circle with a radius of 1/sqrt(pi) metres,an equilateral triangle with sides of 2/fourth root (3) metres.a right angled isosceles triangle with sides of sqrt(2) metres.a square with sides of 1 metres.and so on.
The two equal sides each measure 8 inches
Its not a triangle if it has only two sides.
If the sides of a triangle are doubled then the area becomes quadrupled (four times as large).
Two sides of a triangle are not sufficient to determine its area.
Zero. The two shorter sides together make 70 metres, so they lie flat against the longest side. Really, there is no triangle. If the 3 sides actually make a triangle, you can use Heron's formula - look it up - to find the area.