You add up all the numbers and divide by how many total numbers you have.
Average is normally used for more than one number. Having said that, the average of a single number is itself. In this case 2986.6.
If you have only one number, then its average is that number itself: mean average = sum_of_numbers ÷ number_of_numbers → mean average = the_unknown_number ÷ 1 = the_unknown_number median average = middle number when listed in order; with only one number, it is the middle number → median average = the_unknown_number mode average = most frequent number; if there is more than one number with the same frequency, they are all the mode average; unless every different number occurs the same number of times in which case there is no mode average. With only 1 number, it is the sole most frequent number → mode average = the_unknown_number
You need more than one number to get a proper average. The average of one number itself. So the average of 80.5 would be 80.5 and so 3.0 could not be the average.
3 or 4.
To find the number that is 11 more than 59, you simply add 11 to 59. This calculation results in the number 70. Therefore, 70 is the number that is 11 more than 59.
You need more than one number to find an average.
Five more than twice a number is -13 find the number
You usually need more than one number to have an average, so 160 is the average of 160.
Average is normally used for more than one number. Having said that, the average of a single number is itself. In this case 2986.6.
If you have only one number, then its average is that number itself: mean average = sum_of_numbers ÷ number_of_numbers → mean average = the_unknown_number ÷ 1 = the_unknown_number median average = middle number when listed in order; with only one number, it is the middle number → median average = the_unknown_number mode average = most frequent number; if there is more than one number with the same frequency, they are all the mode average; unless every different number occurs the same number of times in which case there is no mode average. With only 1 number, it is the sole most frequent number → mode average = the_unknown_number
In order to have an average, you need to have more than one figure to add together and then divide.
For an average you generally need more than one number. The average of any one number is itself. So the average of 21.7°C is 21.7°C.
It's impossible.Other AnswerYou need a little more information than the average.
The greater of two numbers is 7 more than the lesser Three times the greater number is 5 more than 4 times the lesser number Find the numbers?
4
You need more than one number to get a proper average. The average of one number itself. So the average of 80.5 would be 80.5 and so 3.0 could not be the average.
-3