5+4x
You cannot find the answer to this question, because you do not know what the number is. If you are looking for how this question looks like algebraically, however, then it is 4n-5.
4x - 5
Assuming that you can use each number multiple times, 3125, because there are five options for the first number, five for the second, and so on to reach five. Then, five times five times five times five times five, or five to the fifth power, equals 3125. Were you only able to use each number once, the answer would be 120 based on the same principle. There would be five options for the first number, four remaining options for the second, three for the third, two for the fourth, and then one for the fifth. Then, as with the first, five times four times three times two (times one, but that really isn't necessary) results in 120.
Four times five is twenty - 4 x 5 = 20
87912 = 4 x 21978
12 and 56
4n-5 (Which is four times a number minus 5)
3
4x+5x
5+4x
You cannot find the answer to this question, because you do not know what the number is. If you are looking for how this question looks like algebraically, however, then it is 4n-5.
commutative
4x - 5
the number is xso the answer would be4x+5=17
Assuming that you can use each number multiple times, 3125, because there are five options for the first number, five for the second, and so on to reach five. Then, five times five times five times five times five, or five to the fifth power, equals 3125. Were you only able to use each number once, the answer would be 120 based on the same principle. There would be five options for the first number, four remaining options for the second, three for the third, two for the fourth, and then one for the fifth. Then, as with the first, five times four times three times two (times one, but that really isn't necessary) results in 120.
Four times five is twenty - 4 x 5 = 20