Just multiply by pi. 2.25 x 3.14 = 7.065
Simply multiply the diameter times pi.
9.00
Circumference = 2*pi*r = 1413.7 cm = 14.137 metres
The area of the circle: pi*15*15 = 225*pi square measurements
Area of the circle = pi R2 = (225 pi) square feetVolume = (225 pi) x (0.25) cubic feet1 cubic yard = 27 cubic feetVolume = (225 pi) / (4 x 27) = 6.545 cubic yards (rounded)
Simply multiply the diameter times pi.
The given measure, 225*pi cm is a linear measure so it cannot refer to the area. It could refer to the radius or the circumference of the circles, or the length of an arc or a segment of the circle. It could, of course refer to something else, but then the task of finding the diameter is near impossible. If it is the length of an arc or a segment, you require further information. Since that is not provided, perhaps one can assume that the measure does not refer to either. That leaves the radius or the circumference. If the radius is 225*pi then the diameter is simply 2*radius = 450*pi cm. If the circumference is 225*pi, then the diameter is circumference/pi = 225 cm.
diameter = 30 units area = 225*pi square units
9.00
Circumference = 2*pi*r = 1413.7 cm = 14.137 metres
pi * 225/4 Radius is 15/2 pi r2 = pi * (15/2)2 = pi * 225/4
Circumference = pi*diameter = 3.14*30 = 94.2 unitsArea = pi * r2 = 3.14 x (30/2)2 = 3.14 x 225 = 706.5 square units
The area of the circle: pi*15*15 = 225*pi square measurements
There are: 225*pi sq feet
The perimeter of a circle is called the circumfernece.Circumference = Pi * d, where d is the diameter of the circle.Area = Pi * r2 , where r is the radius of the circle.=> d*Pi = 450{divide by Pi on both sides}=> d = 450/Pi{r = d/2, use substiution}=> r = 225/Pi{substitute in to Area formula}=> Area = Pi * (225/Pi)2{simplify}=> Area = 2252/PiArea of a circle with a circumference of 450m = 16114.43799m2
Area = 706.5 Area of a circle = pi x r2 Diameter = 30, then radius = 15 pi x r2 3.14 x 152 3.14 x 225 = 706.5
Area of circle = Pi/4 x diameter2 = Pi/4 x 225 = 56.25 Pi = 176.7146 square metres.