You take the square root of X( subpoint 2) minus x subpoint 1 plus y 2 minus y1
To find the approximate distance between the points (45) and (1013) on a coordinate grid, we can treat these as two separate points on a number line. The distance is calculated as the absolute difference between the two values: |1013 - 45| = 968. Therefore, the approximate distance between the points is 968 units.
-- Square the difference between their 'x'-values. -- Square the difference between their 'y'-values. -- Add the two squares. -- Take the square-root of the sum. The result is the distance between the points.
7.07
3.61 units
No.
-- Square the difference between their 'x'-values. -- Square the difference between their 'y'-values. -- Add the two squares. -- Take the square-root of the sum. The result is the distance between the points.
50
3.61 units
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
7.07
3.61 units
3.61 units
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
No.
7.61
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places