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Q: Can you accurately find a diagonal distance on a grid by only counting the grids between them?

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The distance is 5. The x distance is 3, the y distance is 4, and the diagonal issqrt(32 + 42) = sqrt (9 + 16) = sqrt 25 = 5

Example: 3/4 = .750 .750 x 1.1547 = .8660

It is the distance between opposite corners and it can be worked by using Pythagoras' theorem.

Diagonal means a line that is not vertical or horizontal, but in between. i.e. / or \

counting number between 50 and 75

Related questions

It is the distance between opposite corners and it can be worked by using Pythagoras' theorem.

It is the longest distance between two opposite corners of the square and it is possible to use Pythagoras' theorem to find the length of the diagonal

The distance between two tetrahedral voids is 0.866*edge length of the cube.As tetrahedral voids are present at 1/4th of the distance from each corner on a body diagonal of a cube.On each body diagonal there are two tetrahedral voids so making a total of 8 tetrahedral voids in an FCC cube. the distance between two tetrahedral voids is half of the body diagonal of a cube and the body diagonal of a cube is1.732 times of the edge length of the cube

a stick.

The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 and a vertical distance y2-y1 . The square root of the squares gives the diagonal (hypotenuse). In this case, the y difference is 0, so the distance is simply the x change of 4.

Monitor size or Screen size is determined by the diagonal distance between two Corners.

The distance is 5. The x distance is 3, the y distance is 4, and the diagonal issqrt(32 + 42) = sqrt (9 + 16) = sqrt 25 = 5

You must know something else. Like an angle. Or coordinates of the vertices on an x-y plane. And, of course the length of a side. If you know an angle, then you know them all, adjacent angles are supplementary. use law of cosines to find the length of a diagonal. 1/2 of the diagonal is the distance to the opposite vertices. Use law of cosines with the adjacent angle to find the length of the 2nd diagonal. 1/2 of this 2nd diagonal is the distance from the center to the other two vertices.

Example: 3/4 = .750 .750 x 1.1547 = .8660

Between three and four times the diagonal width of the screen (which is the manufacturer's size measurement).

The distance between two integers is the difference.

Its accurately measured as the leakage of information , deliberate attempt to talk, and manipulation. It depends on how you comprehend the distance and how the person whom it is meant does.