To find the domain of the function ( f(x) = x^2 + 1 ), we identify the set of all possible input values for ( x ). Since this is a polynomial function, the domain is all real numbers, expressed as ( (-\infty, \infty) ). The range is determined by analyzing the output values; the minimum value of ( f(x) ) occurs at ( x = 0 ), giving ( f(0) = 1 ). Therefore, the range is ( [1, \infty) ).
sin(x)-cos(x) = (1)sin(x)+(-1)cos(x) so the range is sqrt((1)^2+(-1)^2)=1 and the domain is R <><><><><> The domain of sin x - cos x is [-infinity, +infinity]. The range of sin x - cos x is [-1.414, +1.414].
The range of cosine is [-1, 1] which is, therefore, the domain of cos-1. As a result, cos-1(2) is not defined.
The domain would be (...-2,-1,0,1,2...); the range: (12)
To find the domain and range in ordered pairs, first, identify the set of all first elements (x-values) from each ordered pair for the domain. For the range, identify the set of all second elements (y-values) from the same pairs. For example, in the ordered pairs (2, 3), (4, 5), and (2, 6), the domain is {2, 4} and the range is {3, 5, 6}. Make sure to list each element only once in the final sets.
y=x^2
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
The answer depends on the domain. If the domain is the whole of the real numbers, the range in y ≥ 1. However, you can choose to have the domain as [1, 2] in which case the range will be [2, 5]. If you choose another domain you will get another range.
sin(x)-cos(x) = (1)sin(x)+(-1)cos(x) so the range is sqrt((1)^2+(-1)^2)=1 and the domain is R <><><><><> The domain of sin x - cos x is [-infinity, +infinity]. The range of sin x - cos x is [-1.414, +1.414].
the domain is all real numbers and the range is all real numbers the domain is all real numbers and the range is all real numbers
That depends on the specific function.
The range could be anything. Without parameters specified, the domain of {1,2,3,4} could have any range. This problem is unsolvable.
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.
The range is {-5, -2, 1, 4}
The range of cosine is [-1, 1] which is, therefore, the domain of cos-1. As a result, cos-1(2) is not defined.
x y -3 2 -1 6 1 -2 3 5
The domain would be (...-2,-1,0,1,2...); the range: (12)
To find the domain and range in ordered pairs, first, identify the set of all first elements (x-values) from each ordered pair for the domain. For the range, identify the set of all second elements (y-values) from the same pairs. For example, in the ordered pairs (2, 3), (4, 5), and (2, 6), the domain is {2, 4} and the range is {3, 5, 6}. Make sure to list each element only once in the final sets.