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You use the well-known point-point formula . Here is it: suppose P1 = (x1,y1)
and P2 = (x2,y2) An equation for the line containing P1 and P2 is
y - y1 = [(y1-y2)/(x1-x2)] (x -x1)
Note that the quantity in brackets is the slope of the line. Note also that it does not matter which point is P1 and which is P2.
What else can I help you with?
How do you know if a quadratic equation will have one two or no solutions How do you find a quadratic equation if you are only given the solution Is it possible to have different quadratic equation?
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
How do you find slope if the points aren't given?
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
When two planes equation given and one parametric equation is given how can you find the plane equation?
If you have two equations give AND one parametric equation why do you need to find yet another equation?
How can find the equation of a line when given the x y coordinates?
To find the equation of a line given two points with coordinates (x₁, y₁) and (x₂, y₂), first calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Then, use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to write the equation of the line. You can also rearrange this into slope-intercept form ( y = mx + b ) by solving for y and substituting the slope and one of the points to find the y-intercept (b).
How do you find C in a standard form equation?
In a standard form equation of a linear equation, represented as (Ax + By = C), (C) is the constant term on the right side of the equation. To find (C), you can rearrange the equation by isolating it on one side. For example, if you have (Ax + By = k), then (C) is simply (k). If you're given points or other information, substitute those values into the equation to solve for (C).
How do you know if a quadratic equation will have one two or no solutions How do you find a quadratic equation if you are only given the solution Is it possible to have different quadratic equation?
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
How do you find slope if the points aren't given?
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
How do you find Slope intercept equation of given two points?
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
When two planes equation given and one parametric equation is given how can you find the plane equation?
If you have two equations give AND one parametric equation why do you need to find yet another equation?
How do you find the equation of a parabola in standard form given 3 points?
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
What is the least needed information to find the equation of a line?
The least needed information can be given in different formats, which are equivalent: -- the slope of the line and its intercept on either axis -- the slope of the line and any one point on it -- any two points on the line
How can find the equation of a line when given the x y coordinates?
To find the equation of a line given two points with coordinates (x₁, y₁) and (x₂, y₂), first calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Then, use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to write the equation of the line. You can also rearrange this into slope-intercept form ( y = mx + b ) by solving for y and substituting the slope and one of the points to find the y-intercept (b).
Find the equation of line whose intercepts are-16 for x and y respectively?
The equation is -x -16 equals y. You find this by using the equation for a line mx plus b equals y, where 'm' is the slope and 'b' is the y-intercept. From the information given, you have two points which are 0.-16 ans -16,0. You can find 'm' the slope with the equation y2-y1/x2-x1, or -16-0/0- -16. This is -16/16 or -1 for m and the y-intercept is given as -16. So, substitute into the line equation these values to get the answer given.
How do you find C in a standard form equation?
In a standard form equation of a linear equation, represented as (Ax + By = C), (C) is the constant term on the right side of the equation. To find (C), you can rearrange the equation by isolating it on one side. For example, if you have (Ax + By = k), then (C) is simply (k). If you're given points or other information, substitute those values into the equation to solve for (C).
Is it easier to solve an equation for y first before finding points?
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
How do you find 3 different ordered pairs that are solutions of the equation?
Select any three values of x in the domain of the equation. Solve the equation at these three points for the other variable, y. Then each (x, y) will be an ordered pair that is a solution of the equation.
