Using the Circle Unit which is a chart used in precal and calc classes, you can see that angle 150 in radians is 5pi/6. Using this, the cot value is -Root3.
You cannot because you do not know what R is.
5cm
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. However, I am assuming the question is about sin (5pi/12). If not, please resubmit your question spelling out the symbols as "plus", "minus", "times" sin(5pi/12) = sin(pi/4 + pi/6) = sin(pi/4)*cos(pi/6) + cos(pi/4)*sin(pi/6) = √2/2*√3/2 + √2/2*1/2 = √2(√3 + 1)/4
cos (3pi x/3) = 0.5 The number of answers depends on the range of angles. I will solve this question using the range 0<x<2 pi. Draw a unit circle, you will see that the quadrants where cosine gives a positive value are the first and the fourth quadrants. The Angles whose cosines give + 0.5 are: pi / 3 and 5pi / 3. (Note that 7 pi/3 and 11 pi/3 are also possible solutions but they lie out of the range 0<x<2pi.) 3pi x/3 = pi/3 OR 3pi x/3 = 5pi/3 Here you can solve the equations to give x = 1/3; 5/3
Using the Circle Unit which is a chart used in precal and calc classes, you can see that angle 150 in radians is 5pi/6. Using this, the cot value is -Root3.
You cannot because you do not know what R is.
-5pi/2
5cm
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. However, I am assuming the question is about sin (5pi/12). If not, please resubmit your question spelling out the symbols as "plus", "minus", "times" sin(5pi/12) = sin(pi/4 + pi/6) = sin(pi/4)*cos(pi/6) + cos(pi/4)*sin(pi/6) = √2/2*√3/2 + √2/2*1/2 = √2(√3 + 1)/4
We have a formula of finding the arc length, s = θr, where s is the length of the intercepted arc, θ is the central angle measured in radians, and r is the radius of the circle. So that we need to convert 50 degrees in radians. 1 degrees = pi/180 radians 50 degrees = 50(pi/180) radians = 5pi/18 radians s = θr (replace θ with 5pi/18, and r with 3.5) s = (5pi/18)(3.5) = (17.5/18) pi ≈ 3 Thus, the length of the arc is about 3.
The sine of an angle returns a dimensionless ratio, not an angle, which can be measured in either degrees or radians (or gradians, if you want to get technical). Sines and other trigonometric functions except angles as input to return this ratio. The sine of 50 degrees is .766044443119. The sine of 50 radians is -.262374853704.
cos (3pi x/3) = 0.5 The number of answers depends on the range of angles. I will solve this question using the range 0<x<2 pi. Draw a unit circle, you will see that the quadrants where cosine gives a positive value are the first and the fourth quadrants. The Angles whose cosines give + 0.5 are: pi / 3 and 5pi / 3. (Note that 7 pi/3 and 11 pi/3 are also possible solutions but they lie out of the range 0<x<2pi.) 3pi x/3 = pi/3 OR 3pi x/3 = 5pi/3 Here you can solve the equations to give x = 1/3; 5/3
sin(60) or sin(PI/3) = sqrt(3)/2 cos(60) or cos(PI/3)=1/2 tan(60) or tan(PI/3) = sin(60)/cos(60)=sqrt(3) But we want tan for -sqrt(3). Tangent is negative in quadrant II and IV. In Quadrant IV, we compute 360-60=300 or 2PI-PI/3 =5PI/3 tan(5PI/3) = -sqrt(3) Tangent is also negative in the second quadrant, so we compute PI-PI/3=2PI/3 or 120 degrees. tan(t)=-sqrt(3) t=5PI/3 or 2PI/3 The period of tan is PI The general solution is t = 5PI/3+ n PI, where n is any integer t = 2PI/3+ n PI, where n is any integer
sec x = 2 cos x = 1/2 x = PI/3 and x=5PI/3 The period of cosine is 2PI The general solutions are: x= PI/3 + 2nPI, where n is any integer x = 5PI/3+2nPI, where n is any integer
Assumed that the circle's radius is 2.5 cm, then circumference is pi x 2 x 2.5 = 5pi cm
It's a cylinder on its side, so v = pir2h = 5pi = Approx 15.7 cuft