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Taking the derivative:

2lnx+2, 2(lnx+1).

Extrema occur at y'=0.

2(lnx+1)=0,lnx=-1

x=e^(-1)=1/e

y=-2/e

So the extrema occurs at (1/e,-2/e)

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12y ago

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Q: How do you find the extreme values of x2lnx?
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