start by differentiating each component
d/dx [x2]=2x
d/dx [lnx]=1/x
product rule
2xlnx+x2/x
simplify (factoring)
x[2ln(x)+1]
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All it means to take the second derivative is to take the derivative of a function twice. For example, say you start with the function y=x2+2x The first derivative would be 2x+2 But when you take the derivative the first derivative you get the second derivative which would be 2
Take the derivative of the function.
(cosx)^2-(sinx)^2
find the derivative of 3 -- 6 x + 10 x + 1000= 2 --18 x + 10 3&2 above xes are powers
Derivative of lnx= (1/x)*(derivative of x) example: Find derivative of ln2x d(ln2x)/dx = (1/2x)*d(2x)/dx = (1/2x)*2===>1/x When the problem is like ln2x^2 or ln-square root of x...., the answer won't come out in form of 1/x.