32/4 = 8 units in length
the perimeter is 32 - a square is an equal sided shape that has 4 sides- just divide 32/4 and you will get 8 - the length of one side of the square is 8. (:
Perimeter: 8+8+8+8 = 32
The answer is Length 4 and Width -8.
It is: 128/4 = 32 which is a side of the square and so 32*pi is the circumference of the circle
The perimeter of the rectangle is 2•66+2•32=196196/4(sides of a square)=49 cm
the perimeter is 32 - a square is an equal sided shape that has 4 sides- just divide 32/4 and you will get 8 - the length of one side of the square is 8. (:
Perimeter: 8+8+8+8 = 32
The answer is Length 4 and Width -8.
It is: 32/4 = 8 and 8*8 = 64 square cm
A square with a perimeter of 32 inches has an area of 64 square inches.
It is: 128/4 = 32 which is a side of the square and so 32*pi is the circumference of the circle
The perimeter of the rectangle is 2•66+2•32=196196/4(sides of a square)=49 cm
32.
To find the least perimeter of a rectangle with a fixed area of 32 square feet, we can use the relationship between area and perimeter. For a rectangle, the area ( A = l \times w ) (length times width) and the perimeter ( P = 2(l + w) ). To minimize the perimeter while keeping the area constant, the rectangle should be a square. The side length of a square with an area of 32 ft² is ( \sqrt{32} ), which is approximately 5.66 ft. Thus, the least perimeter is ( 4 \times \sqrt{32} ), which is approximately 22.63 ft.
32
A square of perimeter 32cm has 4 sides of length 8cm. Area = Side1*Side2 Area = 8cm*8cm Area=64cm2
It is: 128/4 = 32 and 32*32 = 1024 square cm