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How do you find the width and length of a rectangle knowing ONLY the diagonal and its angle?
By using the trigonometric ratios of Sine and Cosine. The diagonal forms the hypotenuse of a right angled triangle with the length and width of the rectangle forming the other two sides of the triangle - the adjacent and opposite sides to the angle. Then: sine = opposite/hypotenuse → opposite = hypotenuse x sine(angle) cosine = adjacent/hypotenuse → adjacent = hypotenuse x cosine(angle)
What is the area of a triangle with a hypotenuse of 11 cm and width of 8cm?
The area of triangle is : 44.0
Area of an isosceles right angled triangle?
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
What is the area of a triangle if its length is 14 and its width is 8?
Assuming a right-angle triangle whose length is vertical, and the width is the base, then (14×8) ÷ 2 = 56 square units.
A right triangle has a hypotenuse of length 15 and a leg of length 11 What is the area of the triangle?
The area is about 56.09 units squared.From the Pythagorean formula, the other leg (width) is sq rt (152 - 112)or sqrt (104), about 10.20A = 1/2 (10.20 x 11) = 112.18 / 2 = 56.09
