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The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
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What is the area of a right isosceles triangle with a hypotenuse is 16 square root 2?
Area of the right isosceles triangle: 0.5*16*16 = 128 square units
What is the area of a triangular prism if the height is W inches the length W inches and the base W inches?
The answer depends on what sort of triangle: right angled, equilateral, isosceles or scalene.
How can you take out the area of a right angled triangle?
multiply the base of the triangle by the height then halve the answer.
What is the area of right angled triangle at the right?
There is no right triangle on the right! (Ignore the length of the hypotenuse of a right triangle.) if you have the length of the two legs (base and the upright side): (base x upright) ÷ 2 = area of the right angle triangle.
What is the formula for isosceles?
do you want to know the area in a isosceles triangle or what?
