Q: How do you find the length of a quadrangle when you have the area and the parrallele widths?

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Widths and lengths are two entirely different things. They don't go into anything other than Length x Width = Area.

Area is length x width. Meanwhile Perimeter is the addition of all the lengths and widths of the entire geometric polygon.

6 is your answer because the box is 3 lengths and 2 widths and its basicly a 3 by 2 box.

you maltiply the length by the wedth the proper way to calculate internal area lenght x the avg width. get three widths and aveg them than mutiply them time the lenght.

Its area is: 7 times 8 = 56 square yards Its perimeter is: 7+8+7+8 = 30 yards

Related questions

Widths and lengths are two entirely different things. They don't go into anything other than Length x Width = Area.

How do you find the area of an unequal quadrangle?

give me incircle radius of a quadrangle

Area is length x width. Meanwhile Perimeter is the addition of all the lengths and widths of the entire geometric polygon.

Yes, if one towel had a length of 6 and a width of 2 it would have an area of 12; if a towel had a length of 4 and a width of 3 it would have an area of 12.

Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .

There is no opposite for a quadrangle, a typically square area or courtyard between buildings, as at a school.

The area of a trapezoid is equal to the height, multiplied by the average of the two widths.

6 is your answer because the box is 3 lengths and 2 widths and its basicly a 3 by 2 box.

you maltiply the length by the wedth the proper way to calculate internal area lenght x the avg width. get three widths and aveg them than mutiply them time the lenght.

9x2 . 2x9 . 18x1 . 1x18 . 3x6 . 6x3 all = 18

Its area is: 7 times 8 = 56 square yards Its perimeter is: 7+8+7+8 = 30 yards