First find the points where the straight line meets with the curve:
x2+2x-7 = 17-3x
x2+2x+3x-7-17 = 0
x2+5x-24 = 0
Solving the above by means of the quadratic equation formula gives x values of -8 and 3
when x = 3, y = 8 and when x = -8, y = 41
(x2-x1)2+(y2-y1)2 = (line length)2
(-8-3)2+(41-8)2 = 1210 and its square root is the length of the line
Length = 11 times the square root of 10 which is about 34.785 units of length
The line x-y = 2 intersects with the curve x^2 -4y^2 = 5 at (2.5, 1/3) and (3, 1) and by using the distance formula its length is 5/6
2
k = 0.1
7*sqrt(2) = 9.899 to 3 dp
They work out as: (-3, 1) and (2, -14)
The line x-y = 2 intersects with the curve x^2 -4y^2 = 5 at (2.5, 1/3) and (3, 1) and by using the distance formula its length is 5/6
2
(2, -2)
It is (-0.3, 0.1)
k = 0.1
7*sqrt(2) = 9.899 to 3 dp
Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)
The graph of distance vs. time squared will usually be a curve rather than a straight line. This curve represents a non-uniform acceleration or changing velocity over time, as opposed to constant velocity where the graph would be a straight line. The shape of the curve will depend on the specific relationship between distance and time squared in the given scenario.
On a 400m track, each straight length is 100m, as well as each curve is 100m, totaling 400.
(52/11, 101/11) and (-2, -11) Rearrange 3x-y = 5 into y = 3x-5 and substitute this into the curve equation and then use the quadratic equation formula to find the values of x which leads to finding the values of y by substituting the values of x into y = 3x-5.
If you mean the coordinates of the line x-y = 2 that intersects the curve of x2-4y2 = 5 Then the coordinates work out as: (3, 1) and (7/3, 1/3)
If you mean: y = 17-3x and y = x^2+2x-7 then the length of the line works out as 11 times square root of 10 or about 34.785 to three decimal places.