First you're going to need to know some more information. Let's say the short leg of the triangle is 4 inches.
To find the long leg you would use the formula:
short leg * the square root of 3= long leg
therefore the long leg would equal 4*the square root of 3 inches
If you want to find the length of the hypotenuse(longest side of the triangle, or the diagonal) you would multiply the short leg by 2
short leg*2=hypotenuse
therefore the hypotenuse is 8 inches
so the side lengths would be:
short leg: 4 in, long leg: 4*squrt of 3 in, and hypotenuse: 8 in
Using trigonometry: tangent = opposite/adjacent
sqrt(3) = 1.732 (rounded)
The shortest leg is 3.72 m long.
Using Pythagoras' theorem for right angle triangles then the other leg is 6 feet long
By using trigonometry that is applicable to a right angle triangle.
In a right triangle with a hypotenuse of 11 and one leg of 8, the other leg is: 7.55
Using trigonometry: tangent = opposite/adjacent
sqrt(3) = 1.732 (rounded)
The hypotenuse is 10 yards long.
Each leg works out as 9.998489886 to comply with Pythagoras' theorem for a right angle triangle.
That depends on what x is: a leg, an angle, what?
The shortest leg is 3.72 m long.
12 cm
If the hypotenuse and a leg of a right triangle are congruent to the hypotenuse and a leg of another right triangle, then the triangles are congruent.
Using Pythagoras' theorem for right angle triangles then the other leg is 6 feet long
10
By using trigonometry that is applicable to a right angle triangle.