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Q: One leg of a right triangle is 5 cm long The hypotenuse is 13 cm long What is the length of the second leg of the triangle Round to the nearest tenth?
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Dircections find the length of the hypotenuse Round to the nearest whole number There are two legs on triagles the first leg is 70m and the second is 100 m what is the hypotenuse?

The hypotenuse is: 122 meters.


If you have a triangle one side is 7 cm and one side is 13 cm what is the length of the missing side?

I don't think there is enough information to answer the question, first of all, is it a right triangle? Second, is the the 13cm the hypotenuse. Assuming that 13cm is the hypotenuse, and the triangle is a right triangle, the equation would be 49+x^2=169


What is the area of a perpendicular triangle?

I do believe you mean RIGHT triangle when you said perpendicular triangle. A right triangle has two legs and a hypotenuse. The area of a right triangle is 1/2 * (first leg) * (second leg) How do you determine which ones are the legs and which one is the hypotenuse? The hypotenuse is ALWAYS the largest number. So, choose the 2 smallest numbers.


How is sin 90 equal to 1?

Buckle up, 'cause we can't draw diagrams here and we have to explain everything. Let's jump. Draw a graph with an x-axis and a y-axis like usual. Don't use graph paper or a ruler unless you have to. Just eyeball the thing. We're going to draw a right triangle on the graph and here's how we'll do it. Start at the origin, (0, 0) and draw a line along the x-axis about "6 or 7 units" long. Now draw a line from the end of the first one straight up (at a right angle to the x-axis) and make it about "2 units" long. Lastly, draw the "slanted" line from the origin up to where the vertical line ended. That last line was the hypotenuse of your nice right triangle. Got a good picture? Super. Let's jump to some review. The trigonometry (trig) function called the "sine" (sin) is the relationship in any right triangle between the length of the opposite side (to an given angle in the triangle) and the length of the hypotenuse of that triangle. It's actually the length of the opposite side of the triangle divided by the length of the hypotenuse of the triangle. This number is a "pure" number without units because the units (inches, feet, miles - whatever) cancel out when the division is made. Now that we've reviewed the sine function, let's take it to our triangle. Look at the angle made by the first line you drew and the last one you drew (which was the hypotenuse). It's the angle with the origin of the graph (0, 0) as the vertex. It's gonna be 25 to 35 degrees or so, ballpark. We don't need to be exact. Now, the sine of that angle is the length of the opposite side divided by the length of the hypotenuse. It's some number between 0 and 1. The hypotenuse is obviously larger, and we'll end up with a fraction or, if you prefer, a decimal number. We don't need to know what it is because we are going to be looking at a "trend" or "shift" as we change our graph. We have some number as the sine, and we're good. Now let's modify our graph and draw a new triangle. Follow closely when we jump. We are going to "keep" the hypotenuse we drew. But we are going to "rotate it up" to make a new triangle. Note that we won't change its length. We're going to "open up" the angle between the x-axis and the hypotenuse. Let's do that by detatching the hypotenuse from the short vertical to the x-axis (which is that little second line we drew). Swing the hypotenuse up (that's counterclockwise from its first position) and put it about "half way" between where it was and where the y-axis is. Got it located? Now "drop a perpendicular" from the end of the hypotenuse to the x-axis, and make the line perpendicular to the x-axis. This forms a new right triangle. And this new triangle has a longer "second side" that is vertical to the x-axis. Let's look at our new triangle. The "new" angle formed by the x-axis and the new location of the hypotenuse is larger than it was. And the sine for that angle has changed. The sine is (again) the length of the opposite side over the length of the hypotenuse, and notice that the "new" opposite side is longer than the old one. (We can call that side, the one perpenducular to the x-axis, the "second side" here.) That means the "new" sine will be a larger fraction or a larger decimal (if you work it that way) than before. We don't know the exact number, but we only need to look at it in comparison to what it was. And it's bigger. So let's rotate the hypotenuse more. Start moving it in a slow but continuous motion in the counterclockwise direction. It's heading for the y-axis as you rotate it. Now focus. The new triangle formed as we rotate the hypotenuse (again, without changing its length) will have a longer and longer "perpendicular" to the x-axis as we move the hypotenuse. Pretend that the second side, the one we keep making longer as we rotate the hypotenuse up, is a rubber band stretching longer and longer as we rotate the hypotenuse. It still has to make a right angle where it is attached to the x-axis, so it must "slide along" that axis toward the origin to keep the angle at 90 degrees. Make sense? The triangle is "getting taller" as we rotate the hypotenuse. And the base is getting shorter and shorter. Through all this, the sine of the angle we are looking at is getting bigger and bigger. See how it works? One more jump. As the hypotenuse is rotated counter clockwise and approaches the y-axis, the length of that "second side" will continue to grow and will actually approach the length of the hypotenuse itself. (The triangle's base gets tinier and tinier through all this.) Our angle is getting bigger and bigger, too, and it is approaching 90 degrees. As the length of the second side approaches the length of the hypotenuse, the sine of the angle, that is, the length of the second side divided by the length of the hypotenuse, actually approaches one. That's because the second side is getting almost as long as the hypotenuse. Closer and closer to vertical we move that hypotenuse. At vertical, that is, when the hypotenuse is rotated to vertical, the triangle "disappears" from view, but imagine what is happeing as we approach this "vanishing point" where the triangle ceases to exist. At 90 degrees, the second side is the exact same length as the hypotenuse. That means the angle formed at the vertex becomes 90 degrees. And the base will be so short as to disappear as well. At the 90 degree point where the hypotenuse has been rotated up to lie along the y-axis, the length of the opposite will equal to the length of the hypotenuse. And the sine of the angle (which is 90 degrees) will be the length of the second side exactly 1 at this point. The sine of an angle varies as the measure of the angle, and as the angle increases in measure from 0 to 90 degrees, the sine of the angle varies from 0 to 1 as we discovered.


How would you construct a right triangle given the length of a leg and the radius of the circumscribed circle?

To construct a right triangle given the radius of the circumscribed circle and the length of a leg, begin with two ideas. First, the diameter of the circle is equal to twice the radius. That's pretty easy. Second, the diameter of the circle is the length of the hypotenuse. The latter is a key to construction. Draw your circle, and draw in a diameter, which is the hypotenuse of the right triangle, as was stated. Now set you compass for the length of the leg of the triangle. With this set, place the point of the compass on one end of the diameter (the hypotenuse of your triangle), and draw an arc through the circumference of the circle. The point on the curve of the circle where the arc intersects it will be a vertex of your right triangle. All that remains is to add the two legs or sides of the triangle. Draw in line segments from each end of the hypotenuse (that diameter) to the point where your arc intersected the curve of the circle. You've constructed your right triangle. Note that any pair of lines that is drawn from the ends of the diameter of a circle to a point on the curve of the circle will create a right triangle.


How do you draw an isoscles right angled triangle?

An isosceles triangle is usually drawn with the two sides of equal length as the legs and the third side as the base. For a right angled isosceles triangle then the hypotenuse is drawn as the base with the two sides of equal length as the legs joining together at a right angle. Draw a circle. Draw a horizontal diameter with a second diameter perpendicular to the first. The hypotenuse is the horizontal diameter. Draw lines from the ends of this diameter to the point where one end of the second diameter meets the circumference. These are the two equal legs of the isosceles triangle. These legs meet at an angle of 90° .


What is the length of the third side of a triangle when the first side is 5 in long and the second side is 3 in long?

Not enough information. If it's a right triangle, and the missing side is a leg, it could be 4 in. If the missing side is the hypotenuse, it would be the square root of 34.


How do you find the second leg to a triangle when the hypotenuse and first leg are known?

I am assuming a right-angled triangle here, or the question has no answer. From Pythagoras's formula, (a^2+b^2) = c^2, where a and b are the lengths of the two shorter edges that form the right-angle, and c is the length of the hypotenuse. Let a and c be known. Then b is the square root of (c^2-a^2).


What is formula of finding the perimeter of a triangle?

Perimeter of a triangle = (length of the first side) plus (length of the second side) plus (length of the third side)


A 30-60-90 triangle has a hypotenuse of length 8.6 what is the length of the longer of the two legs?

The longer leg is about 7.45 units.The ratio of the sides in a 30-60-90 is x, x*(sqrt 3), and 2x (hypotenuse). Because you are given 2x = 8.6, we know the length of one leg is 4.3. For the second leg we multiple that by (sqrt 3) which means the second leg has a length of 7.4478.Or:sin = opp/hyp and sin*hyp = oppTherefore:sin 60 degrees * 8.6 = 7.447818473 units (longer side)sin 30 degrees * 8.6 = 4.3 (shorter side


What is the answer for the triangle 12 cm?

It depends on two things. First, one length, by itself, does not define a triangle. And second, it depends on what the question about the triangle is!


What is the length of an altitude of an equilateral triangle whose side length is 8 square root of 3?

If the length of a side of an equilateral triangle = 8√3, then the altitude bisects the base forming a right angled triangle. The side measuring 8√3 is the hypotenuse, the altitude (A) is one leg and half the base length is the second leg. By Pythagoras, (8√3)2 = (4√3)2 + A2 : A2 = (64 x 3) - (16 x 3) = 48 x 3 = 144 Therefore the altitude, A = √144 = 12