Solve for when the first derivative is equal to zero. If you don't know how to take a derivative, then put the equation into the form y = Ax2 + Bx + C. The derivative of this will be 2Ax + B, so at x = -B / (2*A), and y = -B2/(4*A) + C
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Vertex
The vertex is either the minimum (very bottom) or maximum (very top) of a parabola.
It is either a maximum or minimum value depending on its downwards shape or its upwards shape
A quadratic function can only have either a maximum or a minimum point, not both. The shape of the graph, which is a parabola, determines this: if the parabola opens upwards (the coefficient of the (x^2) term is positive), it has a minimum point; if it opens downwards (the coefficient is negative), it has a maximum point. Therefore, a quadratic function cannot exhibit both extreme values simultaneously.
there can be 0, 1, 2, or infinite intercepts for a parabola 0 intercepts occurs when the parabola does not meet the 2nd line 1 occurs when the parabola intersects a line at the vertex 2 occurs when the line does not intersect at the vertex, but still intersects the parabola infinite occurs when there are 2 parabolas, that although they may be written differently, are the same on a graph.