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How do you find the normal force of a 25 kg object being pulled by a rope at a tension of 120 N along a frictionless surface at an angle of 30 degrees?
I could be totally wrong but I believe you must take into account the forces on the object in the vertical direction.
In this case, the object is being pulled by a rope with a tension of 120 N.
The vertical force would therefore be 120 sin(30)
Normally W = [F normal] with no vertical force. However, since there is a vertical force:
W = [F normal] + [120 sin (30)]
(25 kg X 9.8 m/s2) = [F normal] + [120 sin (30)]
245 N - 60 N = [F normal]
185 N = [F normal]
I apologize if this is incorrect as I haven't been in a physics class in over 4 years. Good luck!
What else can I help you with?
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