You might answer this in a couple of different ways. 11 is the "odd" one, as it is the only "odd" number, while 4, 12 and 18 are all "even".
71 is the 36th odd number. To find the "nth" odd number, multiply the term number (ex: 36) by two, then subtract one.
It sounds like the goal is for each box to have an odd number of pencils. At first it seems impossible, but if one of the boxes can go inside another so that the larger box holds an even # plus the odd number in the smaller box (for a total of an odd number), then you can do it.
Odd + even = odd
The answer depends on which one you want to be the odd one out: A kangaroo is the only marsupial of the four. A mule is the only animal of the four that is sterile. A ferret is the only carnivore of the four. So the donkey is the odd one out: it is the only animal (of the four) for which I cannot find an easy reason!
Answers to Quiz, The Odd One Out
This would be impossible as, seeing as one of the integers would be odd, the result would be an odd number.
The 3rd one and the the 5th one.
One can find odd news stories online on websites, such as NBC News, Metro UK, Mirror Online and News of the Weird. Odd news stories are updated every day.
After (3, 5, 7), you can't have any more such "triplets", since one of the three must needs be a multiple of 3.
If the number is odd, that's the answer. If the number is even, write down all the factors and choose the largest one that is odd.
Go really slow and have one life left
You might answer this in a couple of different ways. 11 is the "odd" one, as it is the only "odd" number, while 4, 12 and 18 are all "even".
71 is the 36th odd number. To find the "nth" odd number, multiply the term number (ex: 36) by two, then subtract one.
There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.
It sounds like the goal is for each box to have an odd number of pencils. At first it seems impossible, but if one of the boxes can go inside another so that the larger box holds an even # plus the odd number in the smaller box (for a total of an odd number), then you can do it.
It is impossible for every one