This would be impossible as, seeing as one of the integers would be odd, the result would be an odd number.
The three numbers added together will equal 228. The average of the three numbers will be 228 / 3 = 76. If you take one even integer from either side of 76, you get 74 and 78.Therefore, the three consecutive even integers which equal 228 are 74, 76 and 78.
The numbers are 55, and 57. Two consecutive integers have an odd sum.
The numbers are 37 and 38.
The numbers are 39 and 40.
The numbers are 97, and 99.
They are: 75+76+77 = 228
The sum of any two consecutive integers must be an odd number. So this question is incorrect.
The three numbers added together will equal 228. The average of the three numbers will be 228 / 3 = 76. If you take one even integer from either side of 76, you get 74 and 78.Therefore, the three consecutive even integers which equal 228 are 74, 76 and 78.
No two consecutive integers have a sum of 2012.
The numbers are 55, and 57. Two consecutive integers have an odd sum.
This has no answer. The sum of three odd integers is always odd.
Not all numbers can be expressed as the sum of consecutive integers. Only certain numbers, specifically those that can be represented in the form of ( n(n+1)/2 + k ) for some integers ( n ) and ( k ), can be written as a sum of consecutive integers. Additionally, even numbers can be expressed as a sum of two or more consecutive integers, while odd numbers can be expressed as a sum of at least three consecutive integers. Thus, while many numbers can be represented this way, not all can be.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
There are two consecutive even integers. The numbers are 118 and 120.
The numbers are 101 and 102.
The numbers are 37 and 39.
The numbers are -53 and -52.