Q: How do you find the perimeter of a 7 in by 25 in base?

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yes. add all sides together to find the perimeter. 7+8+10=25.

Use Pythagoras' theorem to find the hypotenuse which works out as 25cm Perimeter = 25+24+7 = 56cm

You can find out the base by the following way.. Let us consider the example: (25/3)=7 To find its base let as assume it has base r.. Now find the value of r by converting the nums in decimal: (2r+3)/3=7 (As 25 in base r is equal to 2*(r^1) + 5*(r^0) in decimal) 2r+3=21 2r=21-3 2r=18 r=9

26 units.

3+3+7+7 = 20 inches

Related questions

yes. add all sides together to find the perimeter. 7+8+10=25.

Use Pythagoras' theorem to find the hypotenuse which works out as 25cm Perimeter = 25+24+7 = 56cm

You can find out the base by the following way.. Let us consider the example: (25/3)=7 To find its base let as assume it has base r.. Now find the value of r by converting the nums in decimal: (2r+3)/3=7 (As 25 in base r is equal to 2*(r^1) + 5*(r^0) in decimal) 2r+3=21 2r=21-3 2r=18 r=9

Perimeter = 12+12+7+7 = 38 inches

26 units.

Its height is 4 km because 2(4)+2(7) = 22 km which is the perimeter

3+3+7+7 = 20 inches

To find the perimeter we add all the sides together: 6+6+7+7=26m

It is: 7+8+12 = 27 cm

4 + 7 x 2 = 22 inches

It is 125 square units.

How about: 11, 11, and 3 cm or as 7, 7 and 11 cm for its perimeter dimensions