You cannot. There are an infinite number of paralellograms with the same base and height but with different "slant" sides.
Imagine two parallel line segments, one directly above the other. If you were to join their ends together, they would form a rectangle. Now move the top line across. The height remains the same but the slant line becomes longer. Keep going and you can make the slant line longer and longer still.
It is: perimeter minus hypotenus+base = height Area = 0.5*base*height
You multiply the base and the height and then you divide the answers of that by 2. :)
all you have to do is add together the four sides. 2L+2W=Perimeter (L=length or base, W=Width or height)
To find the height of the rectangle, we can use the formula for the perimeter ( P ) of a rectangle, which is ( P = 2 \times (\text{base} + \text{height}) ). Given that the perimeter is 38 and the base is 7, we can set up the equation: ( 38 = 2 \times (7 + \text{height}) ). Simplifying gives ( 19 = 7 + \text{height} ), leading to ( \text{height} = 12 ). Thus, the height of the rectangle is 12.
LA = ph
Height = (Perimeter/2) - Base
It is: perimeter minus hypotenus+base = height Area = 0.5*base*height
8.5
You multiply the base and the height and then you divide the answers of that by 2. :)
all you have to do is add together the four sides. 2L+2W=Perimeter (L=length or base, W=Width or height)
The formula for the area of a parallelogram: Base times Height (BH)
LA = ph
im pretty sure its base*height squared
2*(base) + 2*(height) = perimeter
2 x base + 2 x height= perimeter
12 the base times the height
12 the base times the height