A=pi*r^2, so to find the radius, divide the area by pi and take the square root of that quotient. theta/360=arc length/circumference. C=2pi*r, so multiply the radius you found above by 2pi. Then you have theta/(known value)=(known value)/(known value), so you can now solve for theta!
How to find the area of a fillet. Is it area =0.2146 radius squared
2289.06
The question is not well stated. The answer can't be calculated without knowing the length of the cylinder.
One way would be as follows: Let b represent the length of the base, l the length of each of the two sides, and theta the angle between the base and the two sides of length l. Now drop a perpendicular line from each vertex at the top of the trapezoid to the base. This yields two right triangles and a rectangle in the middle. The height of each right triangle (as well as the height of the rectangle) equals l*sin(theta) [because sin(theta)=opposite/hypotenuse] and the length of the base of each right triangle is l*cos(theta). The base of the rectangle is b minus the lengths of the two right triangles. Area of the trapezoid=2*area of each right triangle+area of the rectangle=2*(1/2)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=b*l*sin(theta)-l2*sin(theta)*cos(theta)
A cylinder with a radius of 7in and a length of 3in has a total surface area of about 439.82 square inches.
How to find the area of a fillet. Is it area =0.2146 radius squared
The area of a sector is 0.5*r^2*theta square units where r is the radius measured in linear units and theta is the angle (measured in radians).
It is not. Knowing its radius or diameter will do just as well.It is not. Knowing its radius or diameter will do just as well.It is not. Knowing its radius or diameter will do just as well.It is not. Knowing its radius or diameter will do just as well.
2289.06
The question is not well stated. The answer can't be calculated without knowing the length of the cylinder.
One way would be as follows: Let b represent the length of the base, l the length of each of the two sides, and theta the angle between the base and the two sides of length l. Now drop a perpendicular line from each vertex at the top of the trapezoid to the base. This yields two right triangles and a rectangle in the middle. The height of each right triangle (as well as the height of the rectangle) equals l*sin(theta) [because sin(theta)=opposite/hypotenuse] and the length of the base of each right triangle is l*cos(theta). The base of the rectangle is b minus the lengths of the two right triangles. Area of the trapezoid=2*area of each right triangle+area of the rectangle=2*(1/2)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=b*l*sin(theta)-l2*sin(theta)*cos(theta)
Since the area of a circle is pi times radius squared, take the radius and square it. Then, multiply that by 3.14, or pi to get the area of the circle.
A cylinder with a radius of 7in and a length of 3in has a total surface area of about 439.82 square inches.
If cylinder radius and cylinder length are known : (pi = 3.141592654 . . . ) > Surface area = ( (2 * pi * radius) * length )
Area of the cone part is pi*r*s (s is the slant height which is the hypotenuse of the triangle formed by the radius and the altitude). cosine(theta) = r/s, so s = r/cos(theta), and A = pi*r*s = pi*r^2 / cos(theta). The area of the circle part is given by pi*r^2. Then just add them together.
Radius is 30 inches.
The radius is 30 inches.