One way would be as follows:
Let b represent the length of the base, l the length of each of the two sides, and theta the angle between the base and the two sides of length l. Now drop a perpendicular line from each vertex at the top of the trapezoid to the base. This yields two right triangles and a rectangle in the middle. The height of each right triangle (as well as the height of the rectangle) equals l*sin(theta) [because sin(theta)=opposite/hypotenuse] and the length of the base of each right triangle is l*cos(theta). The base of the rectangle is b minus the lengths of the two right triangles.
Area of the trapezoid=2*area of each right triangle+area of the rectangle=2*(1/2)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=b*l*sin(theta)-l2*sin(theta)*cos(theta)
a right trapezoid
Two angles must be equal and when added to the third angle should total 180 degrees.
The 45 degrees is an angle. To calculate an area the length and width are needed.
The sine function is used in trigonometric calculations when attempting to find missing side lengths of a right triangle. The sine of an angle in a triangle is equal to the length of the side opposite of that angle divided by the length of the hypotenuse of the triangle. Using this fact you can calculate the length of the hypotenuse if you know an angle measure and the length of one leg of the triangle. You can also calculate the length of a leg of the triangle if you know an angle measure and the length of the hypotenuse.
Let's do an example.Draw an isosceles trapezoid. Let say that the biggest base has a length of 10, and the smallest base has a length of 4.Draw two perpendicular line that pass through the vertices of the smallest base, to the biggest base of the trapezoid.A rectangle is formed whose lengths of its two opposite sides equal to the length of the smallest base of the trapezoid.Then, we can say that the base of the right triangle whose hypotenuse is one one of the congruent sides of the trapezoid is 3, (1/2)(10 -4). So that one of the possibilities of its height (which also is the height of the trapezoid) is 4, and the hypotenuse is 5 (by the Pythagorean triple).Now, in the right triangle whose hypotenuse is one of the congruent sides of the trapezoid, we have:tan (base angle of the trapezoid) = 4/3, andthe base angle angle of the trapezoid = tan-1 (4/3) ≈ 53⁰.Since the sum of the two adjacent angles of the trapezoid is 180⁰, the other angle of the trapezoid is 127⁰.Thus, the base angles of the isosceles trapezoid have a measure of 53⁰, and two other angles have a measure of 127⁰.So, we need to have more information in order to find the angles of the isosceles trapezoid for the given problem.
Draw two parallel lines of unequal length, and connect their end points. If you have a right angle, it is a right trapezoid. If the non-parallel sides are equal in length, it is an isosceles trapezoid.
the tangent of an angle is equal to the length of the opposite side from the angle divided by the length of the side adjacent to the angle.
It fits the description of a trapezoid
To calculate the arc length of a sector: calculate the circumference length, using (pi * diameter), then multiply by (sector angle / 360 degrees) so : (pi * diameter) * (sector angle / 360) = arc length
a right trapezoid
Two angles must be equal and when added to the third angle should total 180 degrees.
The 45 degrees is an angle. To calculate an area the length and width are needed.
The sine function is used in trigonometric calculations when attempting to find missing side lengths of a right triangle. The sine of an angle in a triangle is equal to the length of the side opposite of that angle divided by the length of the hypotenuse of the triangle. Using this fact you can calculate the length of the hypotenuse if you know an angle measure and the length of one leg of the triangle. You can also calculate the length of a leg of the triangle if you know an angle measure and the length of the hypotenuse.
Let's do an example.Draw an isosceles trapezoid. Let say that the biggest base has a length of 10, and the smallest base has a length of 4.Draw two perpendicular line that pass through the vertices of the smallest base, to the biggest base of the trapezoid.A rectangle is formed whose lengths of its two opposite sides equal to the length of the smallest base of the trapezoid.Then, we can say that the base of the right triangle whose hypotenuse is one one of the congruent sides of the trapezoid is 3, (1/2)(10 -4). So that one of the possibilities of its height (which also is the height of the trapezoid) is 4, and the hypotenuse is 5 (by the Pythagorean triple).Now, in the right triangle whose hypotenuse is one of the congruent sides of the trapezoid, we have:tan (base angle of the trapezoid) = 4/3, andthe base angle angle of the trapezoid = tan-1 (4/3) ≈ 53⁰.Since the sum of the two adjacent angles of the trapezoid is 180⁰, the other angle of the trapezoid is 127⁰.Thus, the base angles of the isosceles trapezoid have a measure of 53⁰, and two other angles have a measure of 127⁰.So, we need to have more information in order to find the angles of the isosceles trapezoid for the given problem.
it doesn't normally but it can and still be a trapezoid
the length is: 2rsin(1/2 theta) where r is the radius and theta is the included angle.
Using these two measurements you would calculate the angle using the tangent. In this case: tan (theta) = 1680/2700