Volume and surface area cannot be equal, by definition. Volume is a cubic unit, surface is a square unit. Apples and Oranges. However a radius of 1 will certainly yield 1 no matter how big the exponent.
The way to set it up would be to let x = r in "x times x = x times x times x" then cancel out "x times x" on both sides of the equation and 1 = x.
The following was improved by someone else:
(Note: Volume is a different measurement to area anyway so the question cannot be answered but if you said the" 'values' were equal" -it would work)
We know that V = 4/3 pr3 (or 4pr3 /3) and S = 4pr2So 4pr2 = 4/3pr3 which rearranges to:r=3This is the ONLY POSSIBLE ANSWER. So to answer your question, to find out the radius of a sphere where the volume and the surface area have the same value, you need to put the equations on either side of the equals and simplify and rearrange to get a formula or number. In this case, it had a number. To clarify, the FINAL ANSWER WOULD BE r=3A sphere's volume is measured in cubic units, not square units.
360 units cubed
The surface area of the sphere with the radius doubled is 200 units2.---> Confirmed
No, it rarely is.
The radius of curvature of a spherical surface is the radius of the sphere from which the surface is derived. It is defined as the distance from the center of the sphere to the surface at any point. For a perfect sphere, the radius of curvature is constant and equal to the sphere's radius. This concept is crucial in optics and geometry, as it helps determine how light rays behave when they encounter curved surfaces.
The radius of a sphere is equal to one-half the diameter. If the volume of the sphere is known, then the radius (r) is equal to the cube root of 3/4 of (Volume/pi).
A sphere with a volume of 50 units3 has a radius of 2.29 units. A sphere with twice the radius (4.58 units) has a volume of 402 units3.
A sphere's volume is measured in cubic units, not square units.
The formula for the volume of a sphere is based on the radius of the sphere. It is equal to 4/3 multiplied by pi, multiplied by the radius cubed.
I'm quite sure this is impossible to prove, because the volume of a sphere is not equal to the volume of a cylinder with the same radius and height equal to the sphere's diameter. This can be shown as: Volume of sphere = (4*pi*r3) / 3. Volume of cylinder = pi*r2*h. Here, the height, h, of the cylinder = d = 2r. So, the volume of the cylinder = pi*r2*2r = 2*pi*r3, which obviously does not equal the volume of the sphere. The volume of half a sphere (with radius r) is equal to the volume of a cylinder(whose height is equal to its radius, r) minus the volume of a cone with the same height and radius. Therefore, the volume of a sphere is just double that. If you follow the nearby link, you can see a nice demonstration of that.
360 units cubed
The surface area of the sphere with the radius doubled is 200 units2.---> Confirmed
No, it rarely is.
160
volume is equal to four thirds pie times the radius cubed.
The radius of curvature of a spherical surface is the radius of the sphere from which the surface is derived. It is defined as the distance from the center of the sphere to the surface at any point. For a perfect sphere, the radius of curvature is constant and equal to the sphere's radius. This concept is crucial in optics and geometry, as it helps determine how light rays behave when they encounter curved surfaces.
A sphere with a volume of 45 cubic units has a radius of 2.21 units. If you double the radius to 4.42 units, the volume becomes 362 units3Apex answer: 360 units3