By dividing itImproved Answer:-A rhombus has 4 equal sides and its diagonals bisect each other at 90 degrees thus forming 4 equal right angle triangles and by using Pythagoras' theorem any of the 4 equal sides can be found.
The diagonals bisect each other at right angles. So you could use Pythagoras on half the diagonals. So, if the diagonals are a and b units long, then half the diagonals are a/2 and b/2 units long. Then, by Pythagoras, the sides of the rhombus are sqrt[(a/2)2 + (b/2)2]
The diagonals of a rhombus bisect one another at right angles. So you can use Pythagoras on half the lengths of the diagonals. If the two diagonals ore of lengths a and b, then side2 = (a/2)2 + (b/2)2 or, equivalently, side = 1/2*sqrt(a2 + b2)
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
How about a rhombus or a kite
The diagonals of a rhombus (not rombhus) bisect one another at right angles. The sides of the rhombus form the hypotenuses of triangles whose other sides are half the diagonals. So use Pythagoras.
To find the value of x in a rhombus, use these properties. All sides of a rhombus are the same length. Opposite angles of a rhombus are the same size and measure. Intersection of the diagonals of a rhombus form right angles. Sides are perpendicular. The diagonals of rhombus bisect each other. Adjacent angles add up to 180 degrees.
By dividing itImproved Answer:-A rhombus has 4 equal sides and its diagonals bisect each other at 90 degrees thus forming 4 equal right angle triangles and by using Pythagoras' theorem any of the 4 equal sides can be found.
120,120,60,60
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
The diagonals bisect each other at right angles. So you could use Pythagoras on half the diagonals. So, if the diagonals are a and b units long, then half the diagonals are a/2 and b/2 units long. Then, by Pythagoras, the sides of the rhombus are sqrt[(a/2)2 + (b/2)2]
The diagonals of a rhombus bisect one another at right angles. So you can use Pythagoras on half the lengths of the diagonals. If the two diagonals ore of lengths a and b, then side2 = (a/2)2 + (b/2)2 or, equivalently, side = 1/2*sqrt(a2 + b2)
The answer depends on what information you do have about the rhombus. Assuming that you know the length of the sides and one of the diagonals, then,In the triangle formed by the given diagonal and the sides of the rhombus, you know all three sides. So you can use the cosine rule to calculate the angle between the sides of the rhombus.The other pair of angles in the rhombus are its supplement.So now you know two sides and the included angle of the triangle formed by the missing diagonal and the sides of the rhombus.You can use the cosine rule again to find the missing diagonal.
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
Find the area of a rhombs with diagonals that measure 8 and 10.
The diagonals are not equal in length but thet bisect each other at 90 degrees
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