2x = 8 Divide both sides by 2: x = 4 So, the solution set is {4}
No because x = 2
-2x - 2 = 4-2x = 4 + 2-2x = 6x = 6/-2x = -3Check:-2(-3) - 2 = 46 - 2 = 44 = 4
No. -4 does not equal -2(1).
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
y=2x-4 y=2x-5 y=1 1=2x-4 -2x = -5 x=2/5 the solution is (x,y) = (2/5,1)
x = 0
2x = 8 Divide both sides by 2: x = 4 So, the solution set is {4}
x-3x = -8 -2x = -8 x = 4
x=2
No because x = 2
-2x - 2 = 4-2x = 4 + 2-2x = 6x = 6/-2x = -3Check:-2(-3) - 2 = 46 - 2 = 44 = 4
No. -4 does not equal -2(1).
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
2x + 4 = 14 (subtract 4 from both sides) 2x = 10 (divide both sides by 2) x = 5
2x + 4 = 8Subtract 4 from each side of the equation:2x = 4Divide each side by 2:x = 2
There is no solution for those equations because the lines are parallel so, they never touch.