You do it by using what you are given. Unfortunately, you haven't mentioned
what that is, so we can't be any more specific.
Wiki User
∙ 14y agoF = - k x In this equation, x is the distance that the spring has been stretched or compressed away from its equilibrium position F is the restoring force exerted by the spring. k is the spring constant.
angular frequency = square root (K/m) wher k is spring constant and m = mass linear frequency = 1/2pi times square root (K/m)
It is Newtons per metre.
k is often a constant. We don't know what the constant is, but we know we could find out.
Rate of flow varies as R^4 where R is the radius or Rate of flow = (k) x (R^4)
Measure the force (f) required to compress the spring a given amount (x) then use hooke's law to compute the spring constant (k) (f=kx)
F = - k x In this equation, x is the distance that the spring has been stretched or compressed away from its equilibrium position F is the restoring force exerted by the spring. k is the spring constant.
The spring constant is a measure of stiffness - the ability to resist displacement under a load. It is denoted by K where F = kx where f = load force and x = displacement
You can find out how long a spring has been stretched/compressed by knowing it's elastic constant and the force the spring is exerting trying to go back to it's original shape. F=K*x (Moore's law) F is the force exerted by the spring. K is the elastic constant. X is the displacement of the end of the spring from it's normal position. You want to find x, x = F/K
2k
The expression for the force constant (k) in Hooke's Law is given by the equation F = kx, where F is the force applied, k is the force constant, and x is the displacement from equilibrium. The force constant is a measure of the stiffness of a spring or a bond.
Hooke's law was designed to determine the restoring force of a spring, given its spring constant and the displacement of the spring from its equilibrium position. The law is written as follows: F = -kx; in which "F" is the restoring force, "k" is the spring constant, and "x" is the spring's displacement.
It takes a larger force to compress or pull a spring the same distance as a spring with a smaller spring constant. This is shown in Hooke's law. x=F/k k---is the spring constant F---is the force applied to the spring x is the distance the spring has been compressed
To find the work done in stretching the spring, you can use the formula for potential energy stored in a spring: PE = 0.5 k x^2, where k is the spring constant and x is the displacement. Given the frequency, you can calculate the spring constant using the formula f = 1 / (2π) * sqrt(k / m), where m is the mass. Once you find k, you can then find the potential energy stored in the spring when extended by 15 cm by plugging in the values. The work done in stretching the spring can be calculated by multiplying the force needed to stretch the spring by the distance stretched. The potential energy stored in the spring when extended by 15 cm can be determined by the formula PE = 0.5 k x^2, where k is the spring constant and x is the displacement. Once the spring constant is found using the frequency and mass, you can calculate the energy stored in the spring.
To find the equivalent spring constant, you need to know the distance from the point where the force is applied to the axis of rotation. If this distance is 0.10 meters, then the equivalent spring constant would be 5 N/m (k = τ/θ).
angular frequency = square root (K/m) wher k is spring constant and m = mass linear frequency = 1/2pi times square root (K/m)
In Hooke's law, "x" typically represents the displacement or change in position of an object from its equilibrium position. This displacement is proportional to the restoring force exerted by a spring or elastic material.