There are several ways, but none (other than to use a calculator) are simple. Also, since sqrt(56) is irrational, you will not find an exact value for it.
Bracket the result:
Find two perfect squares on either side.
49 < 56 < 64 so 7 < sqrt(56) < 8
Next add two zeros:
5476 < 5600 < 5625 ie 74 < sqrt(5600) < 75 so that 7.4 < sqrt(56) < 7.5
Again
559504 < 560000 < 561001 ie 748 < sqrt(560000) < 749 so that 7.48 < sqrt(56) < 7.49
and again
55995289 < 56000000 < 56010256 ie 7843 < sqrt(56000000) < 7844 so that 78.43 < sqrt(56) < 78.44
You could continue.
Newton-Raphson Method:
You want the solution of x2 = 56
equivalently, the zero for the equation f(x) = x2 - 56. Leaving aside the calculus for the rationale,
You start with any guess for the answer, x0.
Your next guess is x1 = x0 - (x02 - 56)/(2*x0)
and the next one after that is calculated iteratively.
If you started with x0 = 7
the x1 = 7 - (72 - 56)/(2*7) = 7.5
and so on, until very soon,
x3 = 7.483314774, which is less than one in ten billionth off the correct answer.
Finally, there is a method that resembles long division but I cannot explain it easily and I do not know what it is called so can't refer you to a site where it is described.
sqrt(56) = 7.483 approx.
Root 56 = 7.483314773547882 = 7.48
in decimal form the answer is 18.7082869
4
It is: 7.5
The square root of 3136 is 56.
Square root of 56 = Square root of (4 x 14) = (Square root of 4) x (Square root of 14) = 2 x (Square root of 14) The actual value would be 2 x 3.741 = 7.482
2 square root of 14
± 7.483315
56
sqrt(56) = 7.483 approx.
Root 56 = 7.483314773547882 = 7.48
square root of 3136, square root 3146 56x56
in decimal form the answer is 18.7082869
"7" is the number because its square root is "49" & 49+7=56
4
No. The square root of a positive integer can only be an integer, or an irrational number.