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vector PQ where P(-4, -3) and Q(-2, 2) equivalent vector P'Q' where P'(0, 0) and Q'(2, 5) the magnitude doesn't change so we can compute |P'Q'| = √(22 + 52) = √29
The answer depends on the information that you have about the four points and the manner in which that information is presented. Suppose the 4 points are A, B, C and D and the point that you find is P. If you have the coordinates of A, B, C and D then gradient AP = gradient AB (or any other pair) will suffice. If you have any one of vectors AB (or AC, AD, BC, BD), then vector AP is parallel to vector AB will suffice.
The Resultant Vector minus the other vector
We get the Unit Vector
If they are parallel, you can add them algebraically to get a resultant vector. Then you can resolve the resultant vector to obtain the vector components.