To find the value of alpha when sin(α) = 1/2, you can reference the unit circle or trigonometric values. The angles that satisfy this condition are α = 30° (or π/6 radians) and α = 150° (or 5π/6 radians) in the range of 0° to 360° (or 0 to 2π radians). Additionally, the general solutions can be expressed as α = 30° + 360°k and α = 150° + 360°k, where k is any integer.
2.9
A*sin(x) + cos(x) = 1B*sin(x) - cos(x) = 1Add the two equations: A*sin(x) + B*sin(x) = 2(A+B)*sin(x) = 2sin(x) = 2/(A+B)x = arcsin{2/(A+B)}That is the main solution. There may be others: depending on the range for x.
6.25
55 × sin 43 ÷ sin 23 ≈ 96
y = arcsin( cos 48 ); arcsin may be seen as sin-1 on your calculator.
2.9
The expression (\sin(3\alpha)) can be expanded using the triple angle formula for sine, which is (\sin(3\alpha) = 3\sin(\alpha) - 4\sin^3(\alpha)). This formula allows you to express (\sin(3\alpha)) in terms of (\sin(\alpha)).
Once way is to plot it out, and note the intersection points. One spot is 0.2225400023465516 Follow the Wolfram|Alpha link for more answers.
what is the value of sin 75 degree
sin(405) = square root of 2 divided by 2 which is about 0.7071067812
0.96593 (rounded)
If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.
1
sin 300 = -sin 60 = -sqrt(3)/2 you can get this because using the unit circle.
A*sin(x) + cos(x) = 1B*sin(x) - cos(x) = 1Add the two equations: A*sin(x) + B*sin(x) = 2(A+B)*sin(x) = 2sin(x) = 2/(A+B)x = arcsin{2/(A+B)}That is the main solution. There may be others: depending on the range for x.
The value of tan A is not clear from the question.However, sin A = sqrt[tan^2 A /(tan^2 A + 1)]
To find the value of ( \frac{19 \sin(50^\circ)}{\sin(40^\circ)} ), we can use the sine function values. Using the sine of complementary angles, ( \sin(50^\circ) = \cos(40^\circ) ). Therefore, ( \frac{19 \sin(50^\circ)}{\sin(40^\circ)} = \frac{19 \cos(40^\circ)}{\sin(40^\circ)} = 19 \cot(40^\circ) ). For an exact numerical value, you can compute ( 19 \cot(40^\circ) ) using a calculator.