One component = (magnitude) times (cosine of the angle).
Other component = (magnitude) times (sine of the angle).
In order to decide which is which, we have to know the angle with respect to what.
If they are parallel, you can add them algebraically to get a resultant vector. Then you can resolve the resultant vector to obtain the vector components.
The magnitude alone can't tell you anything about its components. You also need to know its direction.
The angle between the rectangular components of a vector can be found using the arctangent function. If a vector has components (A_x) (horizontal) and (A_y) (vertical), the angle (\theta) between the vector and the horizontal axis is given by (\theta = \tan^{-1}\left(\frac{A_y}{A_x}\right)). The components themselves are at right angles (90 degrees) to each other, as they are defined along perpendicular axes.
Given a vector, speed is the magnitude of the velocity vector, |v|. Consider vector V= IVx + JVy + KVz the magnitude is |V| = ( Vx2 + Vy2 + Vz2)1/2
I disagree with the last response. It is implied that the angle you are speaking of is the angle between the x-axis and the vector (this conventionally where the angle of a vector is always measured from). The function you are asking about is the sine function. previous answer: This question is incorrect, first of all you have to tell the angle between vector and what other thing is formed?
If they are parallel, you can add them algebraically to get a resultant vector. Then you can resolve the resultant vector to obtain the vector components.
I will assume a vector in a plane - in two dimensions. The idea of polar coordinates is that the vector is expressed as its length, and an angle. If you already have the vector in rectangular coordinates, i.e. the x and y components, most scientific calculators have a function that might be labelled R->P, to convert from rectangular coordinates to polar coordinates. Otherwise, use basic trigonometry - but using the specialized function is much faster, if your calculator has it.
In a given coordinate system, the components of a vector represent its magnitude and direction along each axis. Unit vectors are vectors with a magnitude of 1 that point along each axis. The relationship between the components of a vector and the unit vectors is that the components of a vector can be expressed as a combination of the unit vectors multiplied by their respective magnitudes.
Nothing
The magnitude alone can't tell you anything about its components. You also need to know its direction.
The magnitude of a vector is 0 if the magnitude is given to be 0.The magnitude of the resultant of several vectors in n-dimensional space is 0 if and only if the components of the vectors sum to 0 in each of a sewt of n orthogonal directions.
Angular displacement is a vector quantity because it has both magnitude and direction. The direction of angular displacement is determined by the axis of rotation and follows the right-hand rule, while the magnitude is given by the angle of rotation. As a vector, angular displacement can be added, subtracted, and resolved into components, making it useful in calculations that involve rotational motion.
The angle between the rectangular components of a vector can be found using the arctangent function. If a vector has components (A_x) (horizontal) and (A_y) (vertical), the angle (\theta) between the vector and the horizontal axis is given by (\theta = \tan^{-1}\left(\frac{A_y}{A_x}\right)). The components themselves are at right angles (90 degrees) to each other, as they are defined along perpendicular axes.
The four components of force are the scalar/real component, fr and three vector components,Fv= Ifx + Jfy + Kfz. The force is F = fr + Ifx + jfy + Kfz.= fr + Fv. The line of action of the force is the vector Ifx + Jfy +kfz. The rotation angle around the vector axis is given by the arctangent Fv/fr.
Given the vector in angle-radius form? y-component=r sin(theta), x-component=r cos(theta)
Given a vector, speed is the magnitude of the velocity vector, |v|. Consider vector V= IVx + JVy + KVz the magnitude is |V| = ( Vx2 + Vy2 + Vz2)1/2
I disagree with the last response. It is implied that the angle you are speaking of is the angle between the x-axis and the vector (this conventionally where the angle of a vector is always measured from). The function you are asking about is the sine function. previous answer: This question is incorrect, first of all you have to tell the angle between vector and what other thing is formed?