Place it gently on a scale.
arc length/circumference=central angle/360 1/9=central angle/360 central angle=40
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
To find the interior angle of a polygon with 40 sides, you can use the formula for the interior angle: ((n - 2) \times 180^\circ / n), where (n) is the number of sides. For a 40-sided polygon, this becomes ((40 - 2) \times 180^\circ / 40 = 38 \times 180^\circ / 40 = 171^\circ). Therefore, the interior angle of a polygon with 40 sides is 171 degrees.
The answer would actually be 40 because180-140=40.
To find an angle that is coterminal with -40 degrees, you can add or subtract multiples of 360 degrees. In this case, adding 360 degrees gives you 320 degrees, which is coterminal with -40 degrees. Therefore, the angle that is coterminal with -40 degrees is 320 degrees.
In order to find length BC the length of AC or length of the hypotenuse must be given
The unit weight of Angle ISMA 40 is typically around 9.78 kg/m.
arc length/circumference=central angle/360 1/9=central angle/360 central angle=40
40 degrees
40
To find the angle of elevation of the sun, we can use the tangent function. The tangent of an angle is equal to the opposite side (height of the tree) divided by the adjacent side (length of the shadow). So, tan(angle) = height of the tree / length of the shadow. Plugging in the values, we get tan(angle) = 40 / 58. Taking the arctan of both sides gives us the angle, so the angle of elevation of the sun is approximately 33.56 degrees.
yes
40
40 degres
2pi/9 radians or 40 degrees
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
Length of sides is irrelevant. Angles are ((180 - 40)/2) ie 70o