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You can get 13 using four 4s by using the following expression: ( 4 \times 4 - \frac{4}{4} ). This simplifies to ( 16 - 1 = 15 ). However, if aiming for 13 specifically and reconsidering the operations, another approach could involve using factorials or square roots, but a common way is ( 4 + 4 + 4 + \frac{4}{4} ), which equals 13.
What else can I help you with?
How do you get the answer 7 by using four 4s?
4+4-(4/4)
How can you get 4 from using four 4s?
4+4+(4-4) = 4
How do you get 125 by using four 4s?
44-4/4
How do you get 39 using 4 4s?
You can achieve 39 using four 4s with the following expression: ( (4 \times 4 \times 4) - 4/4 ). This simplifies to ( 64 - 1 ), which equals 39.
How many 4s are in 55?
13.75 of them
How do you get the answer 13 using 4 4s?
Probably 45$
How can you make 13 using only 4 4s?
4! - 44/4 = 24 - 11 = 13
How do you get the answer 7 by using four 4s?
4+4-(4/4)
How can make a total of 1000 by using fifteen 4s?
One possible way: Make a 10 using five 4s as follows: 4 + 4 + (4 + 4)/4 = 10 Make another two 10s using five 4s in each. Multiply these three 10s.
How can you get 4 from using four 4s?
4+4+(4-4) = 4
How do you get 125 by using four 4s?
44-4/4
What are some sums that eqaual 100 using only 4s?
If your playing 4 4s, 4! x 4 + root4 + root 4
How do you get 39 using 4 4s?
You can achieve 39 using four 4s with the following expression: ( (4 \times 4 \times 4) - 4/4 ). This simplifies to ( 64 - 1 ), which equals 39.
How do you make 22 using four 4s?
The answer is 4! - [(4+4)/4]
How can you get five using only four 4s?
4!/4 - 4/4 = 5
How do you get 31 by using four 4s and any operation?
4!+(4+4!)/4
How do you make 23 by using four 4s?
4! - sqrt 4 + 4/4
