yrs
15 with a remainder of 2
In a square by definition all sides are equal, and the length of a side may be designated by s. The perimeter, 4s, is apparently stated to be equal to 9s - 15. given these conditions, 4s = 9s - 15; subtracting 4s and adding 15 5o each side results in 15 = 5s or s = 3. However, the language of the problem is ambiguous and could instead be interpreted as 4s = 9(s - 15). If that interpretation is used, 5s = 135, and s would equal 27.
44-4/4
4+4-(4/4)
(4x4)-(4/4) = 15
To make 15 using only four 4s, we can use basic arithmetic operations such as addition, subtraction, multiplication, and division. One way to achieve this is (4 + 4 + 4) - 4 = 12 - 4 = 8. Another way is (4 x 4) - (4 Ă· 4) = 16 - 1 = 15. In total, there are several ways to make 15 using only four 4s, and it requires creative thinking and manipulation of numbers.
You can whiten the netting on white cement 4S using a bleacher.
yrs
Probably 45$
One possible way: Make a 10 using five 4s as follows: 4 + 4 + (4 + 4)/4 = 10 Make another two 10s using five 4s in each. Multiply these three 10s.
15 with a remainder of 2
In a square by definition all sides are equal, and the length of a side may be designated by s. The perimeter, 4s, is apparently stated to be equal to 9s - 15. given these conditions, 4s = 9s - 15; subtracting 4s and adding 15 5o each side results in 15 = 5s or s = 3. However, the language of the problem is ambiguous and could instead be interpreted as 4s = 9(s - 15). If that interpretation is used, 5s = 135, and s would equal 27.
44-4/4
15 years
15-2, 15-4, 15-6, 15-8 and 12 is 20
If your playing 4 4s, 4! x 4 + root4 + root 4